M = (y2 - y1) / (x2 - x1)
Call (3,-4) one point
Call (-2,5) the second point.
m = (5- -4) / (-2 - 3)
m = 9/-5 = - 9 / 5
B<<<< answer
Well 5+2 is 7 and 51/2+21/7 is 57/2
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
#SPJ1
See Quadratic Formula and Determinant's/Delta's formula
:) Brainliest?
Answer:
x = sqrt 2, y = 2
Step-by-step explanation:
45-45-90 triangles have a ratio of 1 : 1 : sqrt2
