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3 years ago

8

The equation SA= 652 can be used to calculate the surface area, SA, of a cube with side length 8. What is the surface area, in s

quare meters, of a cube with a side length of 0.5 meter?

1 answer:

enot [183]3 years ago

8 0

Answer:

hi

Step-by-step explanation:

You might be interested in

{8x [1+(20-6)]}÷ 1/2=

IceJOKER [234]

You would do 20-6 which = 14. + 1 =15. times 8= 120 then divide that by 1/2 = 240 if you do 120 divided by .5 in a calculator thats what you get. i hope that helps you

7 0

3 years ago

company with a large fleet of cars hopes to keep gasoline costs down and sets a goal of attaining a fleet average of at least 26

podryga [215]

Answer:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

$p_v =P(t_{(49)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=25.02$ represent the sample mean

$s=4.83$ represent the sample standard deviation

$n=50$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 26$

Alternative hypothesis: $\mu < 26$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{25.02-26}{\frac{4.83}{\sqrt{50}}}=-1.435$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=50-1=49$

Since is a one sided test the p value would be:

$p_v =P(t_{(49)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant lower than 26 so then the specification is satisfied.

3 0

3 years ago

I need help, does anyone understand this?

Mama L [17]

a so-called zero or solution is really just an x-intercept, in which case we set the dependent variable to 0, namely y = h(x) = 0 and solve for x to get it.

$\bf h(x)=4x^2-8x-60\implies \stackrel{h(x)}{0}=4x^2-8x-60\implies \stackrel{\textit{dividing by 4}}{0=x^2-2x-15} \\\\\\ 0=(x-5)(x+3)\implies x= \begin{cases} 5\\ \boxed{-3} \end{cases}$

why is -3 the smallest? well, -3 is much smaller than 5 :), the further to the left you go on the number line, the smaller the number.

4 0

3 years ago

Read 2 more answers

DerKrebs [107]

Answer:

C

Step-by-step explanation:

Two equations and workout the answer

8 0

3 years ago

Andrew drives through 5 intersections with stoplights on his way to work. He records that he is stopped by a red light in 2 of t

photoshop1234 [79]

Answer:

He should expect to be stopped a total of 16 times

Step-by-step explanation:

What the question is saying is that out of every 5 intersections, he would be stopped at 2.

Now, for forty times in which he passes through an intersection , we want to know the number of times in which he would be stopped

In this case we only need to multiply the probability by the number of times in which he passes an intersection and that would be 2/5 * 40 = 16 times

4 0

3 years ago