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Lady_Fox [76]
3 years ago
6

Please help me with this question.

Mathematics
2 answers:
aniked [119]3 years ago
7 0

<u>         I \\\\\\\\\   I            </u>                                                                                              

      [-1]          -3                                                                                                              <u>    I   \\\\\\\\\\\   I               </u>                                                                                              -2              2                                                                                                            \displaystyle\bf x\in[-1;2)\\-1;0;\underline1\\\\Answer: 1                                                                                                                                                                                                                                    

ruslelena [56]3 years ago
6 0

Answer:

Step-by-step explanation:

-1 ≤ x < 3    Solution set = {-1, 0 ,1 , 2}

-2 < x < 2   Solution set  = {-1 , 0 , 1}

Integer values that satisfies both inequalities are -1 , 0 , 1

You might be interested in
30000 is ____ times as much as 30
drek231 [11]

Answer: 1000


Step-by-step explanation:

Well, what times thirty will equal 30,000

30*x=30000

x=1000

You can also figure this out by seeing how many zeros were added to 30,000.

If you found this helpful, please, if you do not mind giving me brainliest! Thanks! :)

5 0
3 years ago
Jenny owns a salon. She had 150 customers at the end of the third quarter, 151 customers at the beginning of the third quarter,
Ira Lisetskai [31]

There is a 96% customer retention rate for the third quarter.

Given

Jenny owns a salon.

She had 150 customers at the end of the third quarter, 151 customers at the beginning of the third quarter, and five new customers in the third quarter.

<h3>Customer retention rate</h3>

It determines the percentage of customers that the company has retained over a given period.

The customer retention rate is determined by;

\rm Customer \ retention \ rate=\dfrac{Given \ period -New \ customers}{Initial \ number}\times 100

Substitute all the values in the formula;

\rm Customer \ retention \ rate=\dfrac{Given \ period -New \ customers}{Initial \ number}\times 100\\\\\rm Customer \ retention \ rate=\dfrac{150-5}{151}\times 100\\\\ Customer \ retention \ rate=\dfrac{145}{151}\times 100\\\\ Customer \ retention \ rate=0.96 \times 100\\\\ Customer \ retention \ rate=96

Hence, there is a 96% customer retention rate for the third quarter.

To know more about customer retention rate click the link given below.

brainly.com/question/25668470

7 0
2 years ago
Mystery Boxes: Breakout Rooms
ollegr [7]

Answer:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

Step-by-step explanation:

Given

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}

Required

Fill in the box

From the question, the range is:

Range = 60

Range is calculated as:

Range =  Highest - Least

From the box, we have:

Least = 1

So:

60 = Highest  - 1

Highest = 60 +1

Highest = 61

The box, becomes:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question:

IQR = 20 --- interquartile range

This is calculated as:

IQR = Q_3 - Q_1

Q_3 is the median of the upper half while Q_1 is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}

<u>Upper half</u>

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

The quartile is calculated by calculating the median for each of the above halves is calculated as:

Median = \frac{N + 1}{2}th

Where N = 7

So, we have:

Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th

So,

Q_3 = 4th item of the upper halves

Q_1= 4th item of the lower halves

From the upper halves

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

<u></u>

We have:

Q_3 = 32

Q_1 can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

IQR = Q_3 - Q_1

Where Q_3 = 32 and IQR = 20

So:

20 = 32 - Q_1

Q_1 = 32 - 20

Q_1 = 12

So, the lower half becomes:

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}

From this, the updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question, the median is:

Median = 22 and N = 14

To calculate the median, we make use of:

Median = \frac{N + 1}{2}th

Median = \frac{14 + 1}{2}th

Median = \frac{15}{2}th

Median = 7.5th

This means that, the median is the average of the 7th and 8th items.

The 7th and 8th items are blanks.

However, from the question; the mode is:

Mode = 18

Since the values of the box are in increasing order and the average of 18 and 18 do not equal 22 (i.e. the median), then the 7th item is:

7th = 18

The 8th item is calculated as thus:

Median = \frac{1}{2}(7th + 8th)

22= \frac{1}{2}(18 + 8th)

Multiply through by 2

44 = 18 + 8th

8th = 44 - 18

8th = 26

The updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question.

Mean = 26

Mean is calculated as:

Mean = \frac{\sum x}{n}

So, we have:

26= \frac{1 + 2nd + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 12th + 58 + 61}{14}

Collect like terms

26= \frac{ 2nd + 12th+1 + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 58 + 61}{14}

26= \frac{ 2nd + 12th+304}{14}

Multiply through by 14

14 * 26= 2nd + 12th+304

364= 2nd + 12th+304

This gives:

2nd + 12th = 364 - 304

2nd + 12th = 60

From the updated box,

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

We know that:

<em>The 2nd value can only be either 2 or 3</em>

<em>The 12th value can take any of the range 33 to 57</em>

Of these values, the only possible values of 2nd and 12th that give a sum of 60 are:

2nd = 3

12th = 57

i.e.

2nd + 12th = 60

3 + 57 = 60

So, the complete box is:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

6 0
2 years ago
Silvio created a table of the possible outcomes of spinning a spinner divided into 4 equal sections labeled A, B, C, and D and r
fgiga [73]

Answer:

there is a 1/4 chance of getting a on the spinner and there is a 50% percent chance of getting less than 4 on the die.

Step-by-step explanation:

because there are 4 spaces and one answer is shown so yeah

3 0
2 years ago
The Fruit Juice Company sold 5,909,999,222 cans of juice last year. This
elixir [45]
A) 2000000000

5,909,999,222-3,999,002,135= 1,910,997,087 which is closest to answer A
5 0
1 year ago
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