Answer:
52 cards:
26 red and 26 black
P(R) = probability of picking a red card
P(B) = probability of picking a black card
P(R) = P(B) = ¹/₂
If with replacement:
P(R∩B) = (¹/₂)(¹/₂) = ¹/₄
If without replacement:
P(R∩B) = (¹/₂)(²⁶/₅₁) = ¹³/₅₁
8 Balls:
3 red and 5 white
P(R) = probability of picking a red ball
P(W) = probability of picking a white ball
P(R) = ³/₈
P(W) = ⁵/₈
If with replacement:
P(R∩W) ∪ P(W∩R) = (³/₈)(⁵/₈) + (⁵/₈)(³/₈)
= ¹⁵/₆₄ + ¹⁵/₆₄
= ³⁰/₆₄
= ¹⁵/₃₂
If without replacement:
P(R∩W) ∪ P(W∩R) = (³/₈)(⁵/₇) + (⁵/₈)(³/₇)
= ¹⁵/₄₂ + ¹⁵/₄₂
= ³⁰/₄₂
= ⁵/₇
Even Numbers: 2, 4, 6
Possible outcomes
H 1
H 2
H 3
H 4
H 5
H 6
T 1
<u><em>T 2</em></u>
T 3
<u><em>T 4</em></u>
T 5
<u><em>T 6
</em></u>
Probability(tails, even) = 3/12= 1/4
answer:
tell us why the other gardens are needed
Answer:
x = 0
Step-by-step explanation:
First, distribute the -2 to the parentheses:
-14 - 8x = -2(-3x + 7)
-14 - 8x = 6x - 14
Add 14 to both sides:
-8x = 6x
Subtract 6x from both sides:
-14x = 0
Divide each side by -14:
x = 0
So, x = 0