Answer:
Step-by-step explanation:
a_1 = 15
a_2 = a_1 - 3
a_2 = 15 - 3
a_2 = 12
a_3 = a_2 - 3
a_3 = 12 - 3
a_3 = 9
a_4 = a_3 - 3
a_4 = 9 - 3
a_4 = 6
a_5 = 3
a_6 = 0 I'm leaving these last two to expand
a_n = a1 - (n - 1)*d
a_n = 15 - (n - 1)*3
a_n = 15 - 3n + 3
a_n = 18 - 3n
Example
a_6 = 18 - 3*6
a_6 = 0
Problem B
t(1) = 108
t(1 + 1) = 1/3 * 108
t(2) = 36
t(3) = 1/3 * t2
t(3) = 1/3 * 36
t(3) = 12
t(4) =1/3 (t(3))
t(4) = 1/3 * 12
t(4) = 4
t(5) = t4 / 3
t(5) = 4 / 3
t(5) = 1.3333333
So the explicit definition is
t(n) = 108 (1/3)^(n - 1) You could simplify this a little bit by realizing that 108 is made of three 3s.
t(n) = 4 * 3^3 * (1/3)^(n - 1)
t(n) = 4 * (1/3) ^ (n - 4)
Example
t(5) = 108 (1/3)^4
t(5) = 108(1/81)
t(5) = 1.3333333
And using the simplified formula, you get.
t(5) = 4 * (1/3)^1
t(5) = 1.333333 which is the same thing as the original result.
Answer:
5.6 inches
Step-by-step explanation:
let c = length of 'j'
I used the Law of Cosines: 
= 
+ 
-2ab· cosC
= (1.3)^2 + (3.6)^2 - 2(1.3)(3.6) x 0.97
Answer:
Multiply the sum of the length and width by two.
Step-by-step explanation:
Answer:THE ANSWER IS B MY GUY
Step-by-step explanation:
Answer: 350km
Step-by-step explanation:
Since we are informed that the scale of map is 1cm : 70km. Therefore, the actual distance between towns that are 5cm apart on the map will be:
= 5 × 70km
= 350km
Therefore, the answer is 350km
