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MariettaO [177]
3 years ago
7

0.8km need to be convert into hour an minute please help

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

It is not possible

Step-by-step explanation:

Required

Convert 0.8km to hours and minutes

One of the condition for a successful conversion is that: only units of the same metric can be converted.

i.e.

Meters can be converted to feet (they both measure distance)

Days can be converted to years (they both measure time)

Pounds can be converted to grams (they both measure weight)

But in the given question, you attempt to convert from distance to time.

<em>This is not possible, because time and distance are different measurements</em>

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Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
4 years ago
24. A farmstand collected $350 from sales on Wednesday. This amount was $75
larisa [96]

Answer:

$100

Step-by-step explanation:

Given:

  • Wednesday sales = $350

If the amount collected from sales on Wednesday was <u>$75 greater</u> than the amount collected from sales on Tuesday, then Tuesday's sales were $75 <u>less</u> than Wednesday's sales:

  • Tuesday sales = $350 - $75 = $275

If the amount collected from sales on Wednesday was <u>two times as great</u> as the amount collected from sales on Monday, then Monday's sales were <u>half</u> Wednesday's sales:

  • Monday sales = $350 ÷ 2 = $175

To calculate how much more the farmstand collected from sales on Tuesday than it collected on Monday, <u>subtract</u> the Monday sales from the Tuesday sales:

  • $275 - $175 = $100
8 0
2 years ago
Read 2 more answers
Which Expression Can Be Used To Determine the nth term in the pattern below<br> 20,25,30,35,40
maw [93]

Answer:

see explanation

Step-by-step explanation:

These are the terms of an arithmetic sequence with n th term

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

d = 25 - 20 = 30 - 25 = 5 and a = 20, hence

a_{n} = 20 + 5(n - 1) = 20 + 5n - 5 = 5n + 15 ← n th term formula

8 0
3 years ago
Help 6,000 ÷ 20 - 34 × 8 + 12 ×9​
Strike441 [17]
The answer to your question is 136, pretty self explanatory
5 0
3 years ago
A survey of 50 retail stores revealed that the average price of a microwave was $375, with a sample standard deviation of $20 (i
OlgaM077 [116]

Answer: d) $369.31 to $380.69

Step-by-step explanation:

Given;

Mean price x= $375

Standard deviation r= $20

Number of retail stores n = 50

Confidence interval of 95%

Z*(95%) = 1.96

Confidence interval = x+/-Z*(r/√n)

= $375+/- 1.96(20/√50)

= $375+/- 5.69

Confidence interval = ($369.31 to $380.79)

5 0
3 years ago
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