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-Dominant- [34]
3 years ago
11

Scott's company makes solid balls out of scrap metal for various industrial uses. For one project, he must make copper balls tha

t
have a radius of 6 in. If copper costs $0.75 per in, how much will the copper cost to make one ball?
Use 3.14 for I, and do not round your answer.
Mathematics
1 answer:
Phantasy [73]3 years ago
5 0
Explanation is in a file
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1. What is the probability of rolling a number less
Darina [25.2K]

Answer:

1/2

Step-by-step explanation:

There are 2 numbers less than 3. (1 and 2) and one 6 on a dice. Therefore there is a 3 out of 6 chance of rolling one of these 3 numbers (1, 2, and 6). This can be represented as 3/6 which would simplify to 1/2 or 50%.

It can also be found this way...

Probability = Number of desired outcomes ÷ number of possible outcomes. Therefore 3 ÷ 6 = 0.5 which is equal to 50% or 1/2.

I hope you choose my answer so you do well on your assignment! I've gotten an A in math every year :)

3 0
3 years ago
Read 2 more answers
Can someone help me please?
ladessa [460]

Answer:

25/28 thats your answer

4 0
3 years ago
Read 2 more answers
Compare. Select &lt;, &gt;, or=.<br> 6.61? 6.610<br> The awnser is 6.610
Svetach [21]

Answer:

6.61=6.610

Step-by-step explanation:

6.61=6.610

After point we can increase no. Of zero.

8 0
3 years ago
J(h - 9) + 2; use h=9, and j = 8
shepuryov [24]

It should be -6

8(8-9)+2

Step-by-step explanation:

3 0
3 years ago
National statistics show that 23% of men smoke and 18.5% of women smoke. A random sample of 175 men indicated that 45 were smoke
NeTakaya

Answer:

98% C.I. = [-0.1270, 0.0994]

Step-by-step explanation:

Here

p1= proportion of men smokers

p1= 45/175= 0.2571

p2= proportion of women smokers

p2= 42/155= 0.2709

1)  Choose the significance level ∝= 0.02

2) The formula for confidence interval is

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

and

(p1^- p2^) z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

<u>3)  The z value is 2.05</u>

<u>4) Calculations:</u>

(p1^- p2^)- z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(-2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=-0.1270 ( using calculator)

And

(p1^- p2^)z ∝/2sqrt( p1^(1-p1^)/n1 + ( p2^(1-p2^)/n2))

Putting the values

= 0.2571-0.2709)(2.05) sqrt ( 0.2571(1-0.2571)/175+ 0.2709(1-0.2709)/155)

=0.0994  ( using calculator)

and Putting ± 2.05 in the confidence interval formula we get limits (-0.1270, 0.0994)

6 0
3 years ago
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