X-int: (square root of 31 + 6,0) & (square root of 31-6,0)
Y-int: (0,5)
Vertex: (6,-31)
AOS: x=6
Max/Min Value: (6,-31)
Answer:
(c - 2d) (3a - 2b)
Step-by-step explanation:
if you need the steps just ask me in the comments and I’ll type them lol
Answer:e. The sampling distribution of the difference in sample proportion is approximately normal.
Step-by-step explanation:
(200) (0.06) >= 10
(200) (0.94) >=10
(197)(0.086) >=10
(197)(0.914) >= 10
We test the sample proportions of it is normal :
Deer population 1:
Sample size, n1 = 200
Proportion, p1 = 0.06
q = 1 - p = 1 - 0.06 = 0.94
n1 * p = 200 * 0.06 = 12
n1 * q = 200 * 0.94 = 188
Deer population 2:
Sample size, n2 = 197
Proportion, p = 0.086
q = 1 - p = 1 - 0.086 = 0.914
n2 * p = 197 * 0.086 = 16.94
n2 * q = 197 * 0.914 = 180.06
Since for samples and proportions ;
n*p and nq ≥ 10 ;
We cm conclude that the sampling distribution of the difference in sample mean is appropriately normal.
I don't know if this is correct..
warning: I may be wrong
so you have to do a proportion..
it's easy!
x1/y1 = x2/y2
so, plug in the values!
12/8 = x/12
now solve for x.
cross multiply:
8x = 144
divide by 8:
x = 18
there!
Answer:
x^2+4x
Step-by-step explanation:
You simply multiply each term by x
