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taurus [48]
3 years ago
10

How do you solve 3 1/4 - 1 5/6

Mathematics
2 answers:
garik1379 [7]3 years ago
7 0

You would solve 3 1/4 - 1 5/6 like this:

See attached image below:

     

rjkz [21]3 years ago
6 0

Answer:

to solve 3\frac{1}{4} -1\frac{5}{6}  you would first need to convert them from mixed numbers to improper fractions. You can do this by multiplying the denominator with the whole number and then adding the numerator.  Then you should make sure that the denominators are the same. You can do this by first finding a number that they will both multiply into. In this example it is 12. And when changing the denominator you must apply it to the numerator.  So if you multiplied the denominator by 3 then you must multiply the numerator by 3. After you can just minus the numerators. However remember to keep the denominator the same. Then you can change it back into a mixed number by dividing the numerator by the denominator and having that whole number on the side of the fraction . lets say it is \frac{13}{6} then you would divide 13 by 6 which is 2 and a decimal and then minus the number that is multiplied by the numerator and it will give a number that is smaller than the denominator and then it would become 2\frac{1}{6}.

Step-by-step explanation:

1) Change the fractions to improper fractions.

   \frac{13}{4} -\frac{11}{6}

2) Change the  denominator to a common denominator.

\frac{39}{12} -\frac{22}{12}

3) Minus the Numerators.

\frac{39}{12} -\frac{22}{12}=\frac{17}{12}

4) Changing it to a mixed number

=1\frac{5}{12}

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Alexxx [7]

Answer:

48+23(6)½

Step-by-step explanation:

A = l × w

A =[(8-(6)^½) × (9+4(6)^½)]

A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]

A =(72 + 32(6)^½ - 9(6)^½ - 24)

A =(72 - 24 + 32(6)^½ - 9(6)^½)

A =(48 + 23(6)^½)

3 0
3 years ago
1. The sum of four consecutive whole numbers is 110. What is the sum of the least and the greatest of the four numbers?
Trava [24]

Answer:

55

Step-by-step explanation:

the four number is 26+27+28+29

so 26+29=55

3 0
3 years ago
Firing a piece of pottery in a kiln takes place at different temperatures for different amounts of time. The graph below shows t
Komok [63]
Are u gonna post the graph?
8 0
3 years ago
Can you guys please do both with the work please and thank you if you actually do it
salantis [7]

Answer:

  7.  29 cm

  8.  equation: 61 = (x) +(2x -7) +(3x +2); sides 11, 15, 35

Step-by-step explanation:

7. Let w represent the width. The length is 3 less than twice the width, so the length is 2w-3. The perimeter is given by the formula ...

  P = 2(L+W)

Substituting the known values, we have ...

  90 = 2((2w-3) +w)

  45 = 3w -3 . . . . . . . . divide by 2

  15 = w - 1 . . . . . . . . . .divide by 3

  16 = w . . . . . . . . . . . . add 1

  L = 2w -3 = 2(16) -3 = 29

The length of the rectangle is 29 cm.

__

8. The equation that should be used is the one that relates the side lengths to the perimeter.

  P = a + b + c . . . . for sides a, b, c

  61 = (x) +(2x -7) +(3x +2)

  61 = 6x -5 . . . . . . collect terms

  66 = 6x . . . . . . . . add 5

  11 = x . . . . . . . . . . divide by 6

Then the side lengths are ...

  a = x = 11

  b = 2x -7 = 2(11) -7 = 15

  c = 3x +2 = 3(11) +2 = 35

_____

<em>Comment on problem 8</em>

You will notice that the side lengths do not satisfy the triangle inequality: the sum of the short sides is not greater than the long side. <em>These side lengths cannot form a triangle</em>. Cute algebra, but <em>bad geometry</em>.

4 0
3 years ago
Please help!
777dan777 [17]

Answer:

\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}

Step-by-step explanation:

Use formulas for the volumes:

V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.

1. When r=1,

V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.

2. When r=2,

V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.

3. When r=3,

V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.

4. When r=4,

V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.

5. When r=5,

V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.

Note that for all r,

\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.

8 0
3 years ago
Read 2 more answers
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