The code of five digits is of the form:
A B C D F
Where A (the first digit) may be any of 9 digits (because 0 is excluded)
B, C, and D, may be each any of 10 digits (0 - 9)
F (the last digit) may be 0, 2, 4, 6 or 8, i.e. 5 different digits.
So the number of different available codes is:
9 * 10 * 10 * 10 * 5 = 45,000.
Answer: 45,000
Answer:
Yes. I do believe that having a positive attitude about our current situation helps with over coming the struggles of it all.
Explanation:
i once had a negative out look on this online school but now that we've reached the end (at my school I've recognized it wasn't too bad after all while doing the work I've learned it helps to listen to some music or watch an video or two from one of my favorite you-tubers and also talking to my friends through apps.
hope this helps.
Using the knowledge of pseudocodes it will be possible to write a code that calculates the amount of hours worked and giving warnings about it.
<h3>Writing a pseudocode we have that:</h3>
<em>while </em>
<em>if number == 0</em>
<em>break</em>
<em>hours =0 </em>
<em>for i =1 to 5 </em>
<em>hours = hours + time_out[ i ] - time_in[ i ]</em>
<em> If hours >36 : </em>
<em>print ( "Name is " ,name)</em>
<em>print( "No of hours are ",hours)</em>
<em>print("Congratulaion! Your working hours are more than 36")</em>
<em>If hours <30 : #</em>
<em>print ( "Name is " ,name)</em>
<em>print( "No of hours are ",hours)</em>
<em>print("Warning !!!")</em>
<em>End loop</em>
See more about pseudocode at brainly.com/question/13208346
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Answer:
Code is provided in the attachment form
Explanation:
Vector Multiplication code:
Vector_multiplication.c file contains C code.
See attachment no 1 attached below
Classification of Algorithm: For creating elements in vector c of size n, number of scalar multiplications is equal to n. The size of original two vectors scales directly with the number of operations. Hence, it is classified as O(n).