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3 years ago

What is ABC classified as?

Mathematics

2 answers:

Virty [35]3 years ago

8 0

Answer:

the first 1

Step-by-step explanation:

notsponge [240]3 years ago

5 0

Answer:

isosceles

Step-by-step explanation:

because 2 of the sides are the same

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Multiply. 1 1/3x1 3/4 Choose 1 answer:

Sloan [31]

Answer: 2 1/3

Step-by-step explanation:

3 0

3 years ago

Solve for x. 7 x = 4 x + 27 x =

rosijanka [135]

Answer:

x=9

Step-by-step explanation:

7x = 4x + 27

subtract 4x on both sides

3x=27

divide 3 on both sides

x=9

plug in

7(9)=63

4(9)+27=63

63=63

6 0

3 years ago

Read 2 more answers

EASY MATH Find all the zeros of f(x)= x^3 − 6x^2 + 13x − 20 given that 1−2i is a zero. x=

Oduvanchick [21]

Answer:

there is only one zero

Step-by-step explanation: and if it easy why you didint do it just ascking

3 0

3 years ago

The ratio of clown fish to angelfish at a pet store is 5:4. The ratio of angelfish to goldfish is 4:3. There are 60 clown fish a

Ahat [919]

Answer:

48 Anglefish, 36 Goldfish

Step-by-step explanation:

7 0

3 years ago

The point slope form of the equation of the line that passes through (-5-1) and (10.-7) is

Natalka [10]

Answer:

The standard form of the equation for this line can be:

l: 2x + 5y = -15.

Step-by-step explanation:

Start by finding the slope of this line.

For a line that goes through the two points $(x_0, y_0)$ and $(x_1, y_1)$ ,

$\displaystyle \text{Slope} = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}$ .

For this line,

$\displaystyle \text{Slope} = \frac{(-1) - (-7)}{(-5) - 10} = -\frac{2}{5}$ .

Find the slope-point form of this line's equation using

$\displaystyle \text{Slope} = -\frac{2}{5}$ , and
The point $(-5, -1)$ (using the point $(10, -7)$ should also work.)

The slope-point form of the equation of a line

with slope $m$ and
point $(x_{0}, y_{0})$

should be $l:\; y - y_{0} = m(x - x_0)$ .

For this line,

$\displaystyle m = -\frac{2}{5}$ , and
$x_0 = -5$ , and
$y_0 = -1$ .

The equation in slope-point form will be

$\displaystyle l:\; y - (-1) = -\frac{2}{5}(x - (-5))$ .

The standard form of the equation of a line in a cartesian plane is

$l: \; ax + by = c$

where

$a$ , $b$ , and $c$ are integers. $a \ge 0$ .

Multiply both sides of the slope-point form equation of this line by $5$ :

$l:\; 5 y + 5 = -2x -10$ .

Add $(2x-5)$ to both sides of the equation:

$l: \; 2x + 5y = -15$ .

Therefore, the equation of this line in standard form is $l: \; 2x + 5y = -15$ .

7 0

3 years ago