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3 years ago

At what point on the graph of y=1/4x^4 is the tangent line parallel to the line 24x -3y=8

Mathematics

1 answer:

Rama09 [41]3 years ago

3 0

Answer:

a) dy/dx = 4/(2y+1)^2.

(b) y = 4/9 x - 14/9

Step-by-step explanation:

You have the following equation

(1)

(a) You first derivative implicitly the equation (1) respect to x:

next, you solve the last result for dy/dx:

(2)

(b) The equation for the tangent line is given by:

(3)

with yo = -2 and xo = -1

To find the slope m you use the result of the equation (2), because dy/dx evaluated in (-1,-2) is the slope at such point:

m =

Hence, by replacing in the equation (3) you obtain:

hence, the equation for the tangent line is y = 4/9 x - 14/9

(4)

the second derivative for the point (-1,-2) is obtained by replacing y=-2 and dy/dx=m=4/9 in the equation (4):

hence, d2y/dx2 evaluated in (-1,-2) is -64/243

Step-by-step explanation:

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3 years ago

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If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

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$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

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Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

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4 years ago

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Answer:

Step-by-step explanation:

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3 years ago

At what point on the graph of y=1/4x^4 is the tangent line parallel to the line 24x -3y=8￼￼

At what point on the graph of y=1/4x^4 is the tangent line parallel to the line 24x -3y=8