1/3 of 28,50= 9,50
subtract this from 28.50
$19.00 is the sale price
hope this helps
The answer to the above question can be determined as -
Let the point on the left side of P be Q, thus coordinates of Q are (a,1) and point on the right side of P be R, thus coordinates of R will be, (a+4, 1).
Now, it given that, between x coordinates of Q and R is 4, and it can be seen that they are getting divided into half.
So, the x coordinate of P will be - a +
i.e. a + 2
<u>Thus, the x coordinate of P will be a +2.</u>
answer: 10/6 × 3
fill in what missing fractions im just guessing you mean 10/6 × 3/3 = 30/18
Answer:
- Point of Inflection: Does not Exist
- f(x) is concave up when x∈(-∞,-6)
- f(x) is concave down when x∈(-6, ∞)
Step-by-Step Explanation
We are to determine the intervals on which the function
is concave up or down and find the points of inflection.
A function f(x) is concave up in the intervals for which the second derivative of the function
.
A function f(x) is concave down in the intervals for which the second derivative of the function
.
Given ![f(x)=\frac{-7x^2-7}{x+6}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B-7x%5E2-7%7D%7Bx%2B6%7D)
We need to solve for the second derivative of the function.
The first derivative:
Using Quotient Rule:
.
.
The Second derivative:
Similarly applying quotient rule:
![f^{''}(x )=\frac{(x+6)^{2}(14x+84)-( 7x^2+84x+7)(2x+12)}{(x+6)^{4}}](https://tex.z-dn.net/?f=f%5E%7B%27%27%7D%28x%20%29%3D%5Cfrac%7B%28x%2B6%29%5E%7B2%7D%2814x%2B84%29-%28%207x%5E2%2B84x%2B7%29%282x%2B12%29%7D%7B%28x%2B6%29%5E%7B4%7D%7D%20)
![f^{''}(x)=\frac{14(x+6) (x+6) (x+6) -14(x+6)(x^2+12x+1) }{(x+6)^{4}}](https://tex.z-dn.net/?f=f%5E%7B%27%27%7D%28x%29%3D%5Cfrac%7B14%28x%2B6%29%20%28x%2B6%29%20%28x%2B6%29%20-14%28x%2B6%29%28x%5E2%2B12x%2B1%29%20%7D%7B%28x%2B6%29%5E%7B4%7D%7D%20)
![f^{''}(x )=\frac{14(x+6) [(x+6) (x+6) -x^2+12x+1)] }{(x+6)^{4}}](https://tex.z-dn.net/?f=f%5E%7B%27%27%7D%28x%20%29%3D%5Cfrac%7B14%28x%2B6%29%20%5B%28x%2B6%29%20%28x%2B6%29%20-x%5E2%2B12x%2B1%29%5D%20%7D%7B%28x%2B6%29%5E%7B4%7D%7D%20)
![f^{''}(x)=\frac{490 }{(x+6)^{3}}](https://tex.z-dn.net/?f=f%5E%7B%27%27%7D%28x%29%3D%5Cfrac%7B490%20%7D%7B%28x%2B6%29%5E%7B3%7D%7D%20)
Now
is 490, thus
does not have a solution,
However, we determine the point where
is undefined. This point is x=-6.
In the Interval, (-∞,-6), f(x) is concave Up and in the Interval (-6, ∞), f(x) is concave down. It has no Inflection point.