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3 years ago

Which triangle is similar to AJKL? Ο ΔJKM Ο ΔΜΚL Ο ΔKML O ALJK

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

Answer: ALJK

Step-by-step explanation:

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Ricky race $640 in a charity walk last year this year he raised 15% more than he raised last year how much money did Ricky raise

Mashutka [201]

He raised $736.

One way is to multiply 640 x .15 = 96
Add 96 + 640 = 736

8 0

3 years ago

Given limit of f (x) = 4 as x approaches 0. what is limit of one-fourth left-bracket f (x) right-bracket superscript 4 baseline

Otrada [13]

The limit of the given function if $\lim_{x \to 0} f(x)=4$ is 64

<h3>Limit of a function</h3>

Given the following limit of a function expressed as;

$\lim_{x \to 0} f(x)=4$

We are to determine the value of the function

$\frac{1}{4} \lim_{x \to 0} [f(x)]^4$

This can also be expressed as

$\frac{1}{4} \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64$

Hence the limit of the given function if $\lim_{x \to 0} f(x)=4$ is 64

Learn more on limit of a function here: brainly.com/question/23935467

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4 0

2 years ago

Rewrite in simplest terms: -4(5v – 3v – 6) – 9v

julsineya [31]

Answer:

-4 (5v -3v -6) -9v (use the distributive property)

-20v +12v +24 -9v (combine all like terms)

-17v +24

3 0

3 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$