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faust18 [17]
3 years ago
13

F(x)=-x2+8x-1 find f(3) show work

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0
F(3)= -(3)^2+8(3)-1
=14
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How many hectograms are in 45 centigrams?
const2013 [10]

Answer:

0.0045 hectograms are in 45 centigrams

Step-by-step explanation:

5 0
3 years ago
Find the midpoint of CH if C has coordinates (-5,-2) and H has coordinates (9,-4)
Sati [7]

Answer:

(2,1)

Step-by-step explanation:

\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-5,\:-2\right),\:\left(x_2,\:y_2\right)=\left(9,\:4\right)\\\\=\left(\frac{9-5}{2},\:\frac{4-2}{2}\right)\\\\= (\frac{4}{2} , \frac{2}{2} )\\\\=\left(2,\:1\right)

8 0
3 years ago
Read 2 more answers
HELPP PLEASEE!!
Likurg_2 [28]

Answer:

A). Options (C) and (E)

B). 4.8 times

Step-by-step explanation:

Part A

Volume of cylinder (1) = πr²h

                                    = π(6)²(5)

                                    = 565.5 cubic inches

Volume of cone (1) = \frac{1}{3}\pi (r)^2h

                               = \frac{1}{3}(\pi )(6)^2(5)

                               = 188.5 cubic inches

Volume of cylinder (2) = πr²h

                                     = π(6)²(15)

                                     = 1696.5 cubic inches

Volume of cone (2) = \frac{1}{3}\pi (r)^2h

                                = \frac{1}{3}\pi (6)^2(15)

                                = 565.5 cubic inches

Volume of sphere = \frac{4}{3}\pi r^{3}

                              = \frac{4}{3}\pi (6)^{3}

                              = 904.8 cubic inches

Figure having volume greater than 600 cubic inches are cylinder (2) and sphere.

Options (C) and (E) are the correct options.

Part (B)

\frac{\text{Volume of sphere}}{\text{Volume of cone (1)}} = \frac{904.8}{188.5}=4.8

Therefore, volume of sphere is 4.8 times the volume of cone (1).

5 0
3 years ago
By how many degrees did the direction of the boat change
gulaghasi [49]

Answer:

The boat turned <u>39°</u> degrees when it made its first turn.

Step-by-step explanation:

The question is as following:

A boat traveled north for 28 miles, then tuned x° south west and traveled for 25 miles before stopping. When it stopped, the boat was 18 miles from its starting point.

By how many degrees did the direction of the boat change when it made its first turn? Round to the nearest degree.

===================================================

See the attached figure which represent explanation of the problem.

The boat start from point A to point B then stopped at point C

AB = 28 miles, BC = 25 miles and AC = 18 miles.

It is required to find the angle x

By applying the cosine Rule:

AC² = AB² + BC² - 2 * AB * BC * cos x

18² = 28² + 25² - 2 * 28 * 25 * cos x

2 * 28 * 25 * cos x = 28² + 25² - 18²

1400 cos x = 1085

Cos x = 1085/1400 = 0.775

x = Cos⁻¹ 0.775 = 39.2° = 39° to the nearest degree.

So, the boat turned <u>39°</u> degrees when it made its first turn.

8 0
3 years ago
Dont understa 25 pts who can help answer this
Firdavs [7]

Answer:

Where is the question?

Step-by-step explanation:

???

4 0
3 years ago
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