Help me please help

Mathematics

1 answer:

Setler [38]3 years ago

7 0

False and false, the a is in absolute value so it would be a positive and positive is greater than negative

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Solve this system:<br><br> 2x+5y+z=3<br> x-3y+2z=2<br> -x+2y-3z=-7

12345 [234]

Answer:

x= -3

y= 1

z= 4

Step-by-step explanation:

Please see the attached pictures for the full solution.

*I evaluated the determinants using Sarrus' rule (see last picture):

∆= aei +bfg +cdh -gec -hfa -idb

*The symbol '∆' (delta) is usually used to denote a determinant.

4 0

4 years ago

Can someone please give me the answer to the second part of this question?<br> Thank You!

Elena-2011 [213]

Answer:

$\theta=30\textdegree$

Step-by-step explanation:

$(ii)\ \sqrt{3}\tan\ \theta=2\sin \theta\\\\substitute\ \tan\theta=\frac{\sin\theta}{\cos\theta}\\\\\sqrt{3}\frac{\sin\theta}{\cos\theta}=2\sin\theta\\\\Divide\ both\ sides\ by\ \sin\theta.\\\\\sqrt{3}\frac{\sin\theta}{\cos\theta\times \sin\theta}=\frac{2\sin\theta}{\sin\theta}\\\\\frac{\sqrt{3}}{\cos\theta}=\frac{2}{1}\\\\Apply\ cross\ multiplication\\\\2\cos\theta=\sqrt{3}\\\\divide\ both\ sides\ by\ 2\\\\\frac{2\cos\theta}{2}=\frac{\sqrt{3}}{2}\\\\\cos\theta=\frac{\sqrt{3}}{2}\\\\$