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r-ruslan [8.4K]
4 years ago
5

Solve this system: 2x+5y+z=3 x-3y+2z=2 -x+2y-3z=-7

Mathematics
1 answer:
12345 [234]4 years ago
4 0

Answer:

x= -3

y= 1

z= 4

Step-by-step explanation:

Please see the attached pictures for the full solution.

*I evaluated the determinants using Sarrus' rule (see last picture):

∆= aei +bfg +cdh -gec -hfa -idb

*The symbol '∆' (delta) is usually used to denote a determinant.

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Three times a number t minus twelve equals forty
tekilochka [14]
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4 years ago
Each output value is equal to the square of the input value minus<br> five
Ivenika [448]

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We can thus write our values as ordered pairs

(0, 0) - This ordered pair is also referred to as the origin

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6 0
3 years ago
What is the square root of -1​
Bond [772]
It’s the imaginary number i. Remember that rule. Hope this helps
6 0
3 years ago
Read 2 more answers
Breann solved the system of equations below. What mistake did she make in her work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 −
goldfiish [28.3K]

Answer:

No mistake

Step-by-step explanation:

2x + y = 5

x - 2y = 10

y = 5 - 2x

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x = 4

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y =  -3

She made no mistake

You can check by plugging in x = 4 and y = -3 into the original equations . They fit exactly.


5 0
3 years ago
Enter the expression N0e−λt, where N0 is N-naught (an N with a subscript zero) and λ is the lowercase Greek letter lambda.
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4 years ago
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