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2 years ago

Please solve this equation. Thank you!38x-12y = (6+2n)x + (4-n)y

Mathematics

2 answers:

Stells [14]2 years ago

7 0

Answer:

39x -12y = (6n+2n)X+(4-n)y

6+2n=38

2n=38-6

2n=32

n=32÷2

n= 16

Elis [28]2 years ago

3 0

Step-by-step explanation:

the answer is in the above image

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If the base of a Pyramid has an area of 144sq ft And if the slant higher of the pyramid is 10ft what would be the higher of the

pogonyaev

Answer:

the height of the pyramid is 8 ft

Step-by-step explanation:

Considering the base of the pyramid to be square whose area is 144 sq ft

This means the side of the base would be √144 = 12 ft.

Now, if you will imagine a pyramid we can easily observe that

Height(H) , slant height( L=10 ft) and half of the side length( 6ft) make a right angle triangle. We can easily calculate height from Pythagoras theorem as

10^2 = H^2 +6^2

⇒ H^2 = 10^2-6^2 = 100-36 = 64

⇒ H = 8 ft

Therefore, the height of the pyramid is 8 ft

3 0

2 years ago

1. Find "V". Round to hundreds.<br>V = LWH<br>L= 29.4<br>W = 16.7<br>H = 21.8

postnew [5]

Volume = 10,700

V = LWH

L = 29.4

W = 16.7

H = 21.8

All we need to do is multiply them all together and then round the answer to get our final answer to the hundreds place.

V = LWH

V = 29.4(16.7)(21.8)

V = 490.98(21.8)

V = 10703.364

Then, we need to round it to the hundreds place.

V = 10,700

4 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

numerele a, b si c sunt direct proportionale cu 2, 3 si 5. Daca media aritmetica a celor trei numere este egala cu 100, determin

Fynjy0 [20]

Answer:

a = 60

b = 90

c = 150

Step-by-step explanation:

Numerele a, b și c sunt direct proporționale cu 2, 3 și 5.

Unde k este constantă de proporționalitate

a ∝ 2

a = 2k

b ∝ 3

b = 3k

c ∝ 5

c = 5k

Dacă media aritmetică a celor trei numere este egală cu 100, determinați numerele a, b și c

= 2k + 3k + 5k / 3 = 100

= 10k / 3 = 100

Cross Multiply

= 10k = 3 × 100

= 10k = 300

Împărțiți ambele părți la 10

k = 300/10

k = 30

Pentru numărul a

a = 2k

a = 2 × 30

a = 60

Pentru numărul b

b = 3k

b = 3 × 30

b = 90

Pentru numărul c

c = 5k

c = 5 × 30

c = 150

Prin urmare, a = 60, b = 90, c = 150

3 0

3 years ago

What is the equation in slope-intercept form

marta [7]

Answer:

Step-by-step explanation:

Slope is rise/run, so the fraction would be more likely to be the correct answer.

4 0

3 years ago

Please solve this equation. Thank you!38x-12y = (6+2n)x + (4-n)y​​

Please solve this equation. Thank you!38x-12y = (6+2n)x + (4-n)y