Answer:
c) y= -3x + 3
Step-by-step explanation:
Given equation
y= 1/3x+6
Here slope m1 = 1/3
We know that the slope of perpendicular lines
m1*m2 = -1
slope of perpendicular line m2 = -1/m1
= -1/ (1/3)
m2 = -3
Also the line passes through (2, -3)
equation of line is given by y = mx+b
y= -3
x= 2
m2 = -3
Applying above values to the equation of line,
-3 = (-3*2)+b
b=3
Hence equation of perpendicular line is y = -3x + 3
- 31/6 , -26 square rooted, -5, - 5/6
This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3
Second part: when (6x + 2) is negative.
-(6x + 2) < 10 Divide both sides of inequality by -1 and change the sign.
(6x + 2) > -10
6x + 2 > -10
6x > -10 - 2
6x > -12 Divide both sides by 6.
x > -12/6
x > -2.
Combined solution: x < 4/3 and x > -2
-2 < x < 4/3.
Graph is a line on the number line between -2 and 4/3.
-2 and 4/3 are excluded from solution.
The answer is 77 multiply and add them
So my understanding from this you have to make it y = mx + b so m stands for the slope there’s different ways to find it as shown in the first picture. I’ll try to make another comment since this only lets me take one picture at a time.
