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DedPeter [7]
2 years ago
8

Two mixed numbers with different denominators to get 4 1/3

Mathematics
1 answer:
nalin [4]2 years ago
7 0

Answer:

1 2/3 and 2 4/6

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What is the length of side AC of the triangle?
ryzh [129]

Answer:

AC = 25 units

Step-by-step explanation:

Given ∠ A = ∠ C then the triangle is isosceles and BC = AB , that is

7x - 1 = 5x + 5 ( subtract 5x from both sides )

2x - 1 = 5 ( add 1 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

Then

AC = 6x + 7 = 6(3) + 7 = 18 + 7 = 25 units

3 0
3 years ago
The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.
NISA [10]

Answer:

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=8.2 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=2.2 represent the population standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

8.2-2.58\frac{2.2}{\sqrt{18}}=6.86    

8.2+2.58\frac{2.2}{\sqrt{18}}=9.54    

So on this case the 90% confidence interval would be given by (6.86;9.54)    And the error is given by:

ME= 2.58\frac{2.2}{\sqrt{18}} =1.338

8 0
3 years ago
Read 2 more answers
Roberto hikes 21.48 miles on one weekend. The next weekend he hikes 30 miles. How much less is the distance he hiked on the firs
Alex Ar [27]

Answer:

he hiked 8.52 more =)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Hey can you please answer this question on 7th grade exponents? thank you! boo
Ket [755]

A. 75 x 0.0016= .12 Has a value between 0 and 1

B. 3^5 / 3^-6 = 177147 Does not a value between 0 and 1

C. 1/4^3 x 1/4^2 = about 0.0009 Has a value between 0 and 1

D. -7^5 / -7^7 = about 0.02 Has a value between 0 and 1

8 0
3 years ago
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Perform a statistical test for the given problem. Follow the steps in hypothesis testing when you present your results.  
tatyana61 [14]

Using the t-distribution, as we have the standard deviation for the samples, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the treatment increases the survival time of patients.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if the treatment did not increase the survival time, that is, the subtraction of means is 0, hence:

H_0: \mu_T - \mu_W = 0

At the alternative hypothesis, we test if the treatment has increased the survival time, hence:

H_1: \mu_T - \mu_W > 0

<h3>What is the distribution of the differences of means?</h3>

For each sample, we have that:

\mu_W = 2.2625, s_W = \frac{0.75769858}{\sqrt{8}} = 0.2679

\mu_T = 4.5875, s_T = \frac{0.50267143}{\sqrt{8}} = 0.1777

<h3 />

Hence, for the distribution of differences, the mean and the standard error are given by:

\overline{x} = \mu_T - \mu_W = 4.5875 - 2.2625 = 2.325

s = \sqrt{s_W^2 + s_T^2} = \sqrt{0.2679^2 + 0.1777^2} = 0.3215

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.325 - 0}{0.3215}

t = 7.23

<h3>What is the decision?</h3>

Considering a<em> right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>standard significance level of 0.05 and 8 + 8 - 2 = 14 df</em>, we have that the critical value is of t^{\ast} = 1.7613.

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that the treatment increases the survival time of patients.

More can be learned about the t-distribution at brainly.com/question/13873630

8 0
2 years ago
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