-2 and one third > 2 and two third
1 answer:
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Answer: 0.8413
Step-by-step explanation:
Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.
Mean :
Standard deviation :
Let x be the random variable that represents the typing speeds for the students.
The z-score :-
For x= 51
Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-
Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413
Answer:
40
Step-by-step explanation:
The data is
21,24,25,28,29,35,37,43,44
To find the third quartile we have to arrange the data in increasing order
so the data in increasing order is
21,24,25,28,29,35,37,43,44
total number of values = 9
Median value = (n + 1 )/ 2
=(9+1)/2
=5th value
so the median is 29
Lower half of the data is the values before the median and upper half of the data is values after the median
so lower half = {21,24,25,28}
Upper half = {35,37,43,44}
so to find the third quartile we will use the upper half of the values
Third quartile means that the median of the values of upper half of the data
As the total No of value in upper half is 4 which is an even no
we will take the middle values of the upper half and take their mean
so
Third Quartile =
=
=40
so the value of third quartile is 40