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exis [7]
3 years ago
13

Will give brainliest please show your work

Mathematics
2 answers:
Musya8 [376]3 years ago
8 0
Take all the measurements and multiply each one by 2 because there are 2 sides for each measurement and then add your answers all up to get your final answer. For example: here’s what I did for problem 1

Oksanka [162]3 years ago
5 0

Answer:

Step-by-step explanation:

For surface area you wanna find the area of all the sides and then add them up to get surface area

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Helpppp me pleaseeeee!!! This is due in 10 minutes put an explanation pleaseee thank you.
Juliette [100K]

Use cross multiplication

5 0
2 years ago
In college​ basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins
denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.45, n = 100

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b)This is Z when X = 0.25.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.25 – 0.45}{0.0497}

Z = -4.02

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0
3 years ago
Identify the ordered pair that represents the vector from A(-8,-1) to B(-5,3) and the magnitude of vector AB.
wel
In order to find the vector that points from A to B we need to subtract each component of A from the corresponding component of B, according to the formula: v(a→b)=(b1−a1,b2−a2) In this case we have : v(a→b)=(−5−(−8),3−(−1)) <span>v(a→b)=(3,4)

</span>To find the magnitude we use the formula: ||v|=  √(v1^2)+(v1^2)

So:
||v|= √(32)+(42) ||v|=  √9+16 ||v|= <span>√</span>25  ||v|= 5
8 0
3 years ago
What is the radius of a circle in it in if the area is 36m²?
allsm [11]

Answer:

B. 3.39 m

Step-by-step explanation:

r² = A/π

= 36/3.14

= 11.465

r = √11.465 = 3.39

4 0
2 years ago
Alicia has a gold bracelet and a silver bracelet. She has a black ring, a blue ring, a brown ring, and a white ring. She also ha
Artist 52 [7]
This may not be the right answer but I do believe it is 16 different combinations
8 0
3 years ago
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