Answer:
Correct option: C) 90 degrees
Step-by-step explanation:
When we have a tangent segment to a circle, the angle made with the radius of the circle and the tangent segment is always a right angle, that is, 90 degrees. In other words, the radius and the tangent segment are always perpendicular.
If QR is tangent to the circle P, and PQ is the radius of the circle, the segment PQ is perpendicular to the segment QR, so the angle PQR is equal 90 degrees.
Correct option: C)
Answer:
Both child tickets and senior tickets cost $14.
Step-by-step explanation:
Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:
10 senior tickets + 8 child tickets = 252
10 senior tickets + 10 child tickets = 280
280 - 252 = 2 child tickets
28 = 2 child tickets
28/2 = 1 child ticket
14 = 1 child ticket
14 x 10 = 140
(280 - 140) / 10 = senior tickets
140/10 = 14 = senior tickets
Therefore, both child tickets and senior tickets cost $14.
Answer:
Step-by-step explanation:
Given problem: C(x,y) = 36x + 48y
constraint: 100x^0.6y^0.4
Using langrange Multiplier,
36 = 0.6(100)x^-0.4y^0.4λ i
48 = 0.4(100)x^0.6y^-0.6λ ii
dividing the equations we have:
x = 2y
substituting into the constraint
p(x,y) = 100 *(2y)^0.6 y^0.4 = 100*2^0.6 *y
5000 = 151.572y
y = 329.876 labor units
x = 659.752 capital units
Minimum cost = 36(659.752) +48(329.876) = $39585.12
Result: 4h+36
Geometric figure: Line
Alternate form: 4(h+9)
Root: h= -9
