Answer:
#1 - All real numbers are solutions.
#2 - All real numbers are solutions.
Step-by-step explanation:
#1 -
Let's solve your equation step-by-step.
12(6t−4)=3t−2
Step 1: Simplify both sides of the equation.
12(6t−4)=3t−2
(12)(6t)+(12)(−4)=3t+−2(Distribute)
3t+−2=3t+−2
3t−2=3t−2
Step 2: Subtract 3t from both sides.
3t−2−3t=3t−2−3t
−2=−2
Step 3: Add 2 to both sides.
−2+2=−2+2
0=0
Same for #2
The answer is 14. This is because 63=3+x+3x-4. Then You just subtract it and then you get 64=4x. Then you just divide it and then you get x=16.
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
Step-by-step explanation:
interchange x and y
y= 1/(x - 2)
x = 1 / (y - 2) Multiply both sides by y - 2
x(y - 2) = 1 Remove the brackets
xy - 2x = 1 Add x to both sides
xy = 1 + 2x Divide by x
y = (1 + 2x)/x
The brackets have been destroyed. The answer is as I've given it.
y = (1/x) + 2
