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ANTONII [103]
3 years ago
9

What is the standard form of (6x^2-8x-7)+(8x^2-76x)

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:  14x^2 - 84x - 7

====================================================

Explanation:

The like terms 6x^2 and 8x^2 combine to 14x^2

The like terms -8x and -76x combine to -84x

Nothing pairs with the -7, so its stays as is.

Standard form is where we list the terms in decreasing exponent order. We can think of -84x as -84x^1 and the -7 as -7x^0. So 14x^2 - 84x - 7 would be the same as 14x^2 - 84x^1 - 7x^0. The exponents count down: 2,1,0.

The final answer is a trinomial since it has three terms. It is also a quadratic because the degree (highest exponent) is 2.

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Price of 50 kg rice rupees 7650 find the price of 1 kg rice​
Lilit [14]

Answer:

price of 50 kg rice rupees 7650 find the price of 1 kg rice

so 50kg: 7650r

divide both sides by 50 to get 1

1kg=153 rupees

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3 years ago
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A triangular flag has an area of 187.5 square inches. The base of the flag measures 25 inch How tall is the triangular flag?
SpyIntel [72]
To find the height, you would do the area divided by the base, or in this case,187.5 / 25 which equals 7.5 inches.  Hope this helped!
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3 years ago
A popular brand of running
s2008m [1.1K]

$119 - $68 = $51

51/68 x 100 = .75

.75 x 100 = 75%

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3 years ago
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1. Find the value of x.<br><br> A. 90<br> B. 80<br> C. 60<br> D. 45
tia_tia [17]

Answer:

A 90

Step-by-step explanation:

multiple ways to prove this.

e.g. since the angle between the two lines from the center of the circle to the 2 tangent touching points is 90 degrees (that is the meaning of these 90 degrees here as the angle of the circle segment defined by the 2 tangent touching points and the circle center), the tangents have the same "behavior" as tan and cot = the tangents at the norm circle at 0 and 90 degrees. they hit each other outside of the circle again at 90 degrees.

another way

imagine the two right triangles of the tangents crossing point to the circle center and the tangent/circle touching points.

the Hypotenuse of each triangle is cutting the 90 degree angle of the circle segment exactly in half (due to the symmetry principle). so the angle between radius side and Hypotenuse is 90/2 = 45 degrees.

that means also the angle of such a right triangle at the tangent crossing point is 45 degrees (as the sum of all angles in a triangle must be 180, we have the remainder of 180 - 90 - 45 = 45 degrees).

the angles of both right triangles at that point are the same, and so we can add 45+45 = 90 degrees for the total angle at the tangent crossing point.

8 0
3 years ago
Help! I don't understand this
Murljashka [212]

The area of your circle is about 530.93 m

The diameter of your circle is 26 m, just multiply your radius by 2

The circumference of the circle is about 81.68


The equation to finding the area is

pi x r x 2

3.14 times 13 times 2

The equation to finding the diameter

r x 2

radius times 2

The equation for finding circumference

pi x d

3.14 times 26

Let me know if im wrong, otherwise I want brainliest, PLEASE!!

8 0
3 years ago
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