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katen-ka-za [31]
3 years ago
5

Question in the screenshot! :D help me ;D :D :D :D

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

23 units in total? If not its (side A- 14) (Side B- 9) 14+9=23 but i could be wrong

Step-by-step explanation:

I'm pretty sure mostly if you are combining them but they are both different numbers when added together ->-

You might be interested in
If y varies inversely as x, and y = 10 when x = 20,<br> find x when y = 16.
Ipatiy [6.2K]

Answer:

12.5

Step-by-step explanation:

y varies inversely as x.

y = k/x

10 = k/20

200 = k

The constant proportion k is 200.

16 = 200/x

Cross multiply.

200 = 16x

200/16 = x

x = 12.5

5 0
3 years ago
Translate the sentence into an inequality.
Vadim26 [7]

Answer:

9(n + 22) ≤ -15

Step-by-step explanation:

9 times the sum of a number and 22 is at most −15

Let n = number

Times = multiplication

Sum = Addition

9 * n + 22

We must add parenthesis on the end on 22 and before n

We must do this because it says 9 times the sum of a number and 22 which means that 9 is being multiplied by both n and 22

We would have 9(n + 22)

9(n + 22) is at most -15

At most meaning that -15 is the highest number that 9(n + 22) can equal

Because it says at most 9(n + 22) can equal -15 or anything less than -15

So at most can be replaced with ≤

9(n + 22) ≤ -15

4 0
3 years ago
(a) If G is a finite group of even order, show that there must be an element a = e, such that a−1 = a (b) Give an example to sho
Dahasolnce [82]

Answer:

See proof below

Step-by-step explanation:

First, notice that if a≠e and a^-1=a, then a²=e (this is an equivalent way of formulating the problem).

a) Since G has even order, |G|=2n for some positive number n. Let e be the identity element of G. Then A=G\{e} is a set with 2n-1 elements.

Now reason inductively with A by "pairing elements with its inverses":

List A as A={a1,a2,a3,...,a_(2n-1)}. If a1²=e, then we have proved the theorem.

If not, then a1^(-1)≠a1, hence a1^(-1)=aj for some j>1 (it is impossible that a^(-1)=e, since e is the only element in G such that e^(-1)=e). Reorder the elements of A in such a way that a2=a^(-1), therefore a2^(-1)=a1.

Now consider the set A\{a1,a2}={a3,a4,...,a_(2n-1)}. If a3²=e, then we have proved the theorem.

If not, then a3^(-1)≠a1, hence we can reorder this set to get a3^(-1)=a4 (it is impossible that a^(-1)∈{e,a1,a2} because inverses are unique and e^(-1)=e, a1^(-1)=a2, a2^(-1)=a1 and a3∉{e,a1,a2}.

Again, consider A\{a1,a2,a3,a4}={a5,a6,...,a_(2n-1)} and repeat this reasoning. In the k-th step, either we proved the theorem, or obtained that a_(2k-1)^(-1)=a_(2k)

After n-1 steps, if the theorem has not been proven, we end up with the set A\{a1,a2,a3,a4,...,a_(2n-3), a_(2n-2)}={a_(2n-1)}. By process of elimination, we must have that a_(2n-1)^(-1)=a_(2n-1), since this last element was not chosen from any of the previous inverses. Additionally, a_(2n1)≠e by construction. Hence, in any case, the statement holds true.

b) Consider the group (Z3,+), the integers modulo 3 with addition modulo 3. (Z3={0,1,2}). Z3 has odd order, namely |Z3|=3.

Here, e=0. Note that 1²=1+1=2≠e, and 2²=2+2=4mod3=1≠e. Therefore the conclusion of part a) does not hold

7 0
3 years ago
6. You roll a 6 sided die and flip a coin. What is the
MakcuM [25]

Answer:

for the die it's a 4 to 6 chance and the coin is a 50% chance

5 0
2 years ago
If f(x) = 2x2 + 1, what is f(x) when x = 3? a.1 b.7 c.13 d.19
prohojiy [21]

<u>Answer:</u>

The value of f(x) = 2x^2 + 1 when x=3 is 19, hence the correct option is ‘d’.

<u>Solution:</u>

A two degree polynomial equation is given in the question.

The equation is:

F(x)=2 x^{2}+1

We need <em>to find the value of f(x) when the value of x is 3. </em>

To solve a question like this we have to substitute the given value of x in the given equation and then simplify it.

Now let's substitute the value of x in the given equation.

F(x)=2(3)^{2}+1

First we square the number 3 and then multiply it with 2 and then add 1.

This is done because of the BODMAS rule, in which multiplication is given higher preference as compared to addition.

On solving the equation we get,

F(x)=2×9+1

F(x)=18+1

F(x)=19.

Therefore the value of f(x) when x=3 is 19.

Hence the correct option is ‘d’.

4 0
3 years ago
Read 2 more answers
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