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abruzzese [7]
3 years ago
10

Please help- as soon as possible- Multiply (a+2) (a-4)=

Mathematics
1 answer:
Tresset [83]3 years ago
8 0

Answer:

a2+2a−8

Step-by-step explanation:

Expand (a+4)(a−2)(a+4)(a-2) using the FOIL Method.

a⋅a+a⋅−2+4a+4⋅−2

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  \bf _nP_r=\cfrac{n!}{(n-r)!}\qquad \qquad _4P_1=\cfrac{4!}{(4-1)!}
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4 years ago
If a + b+ c = 9 and ab + bc + ca = 26, find a2 + b2 + c2.​
alex41 [277]

Answer:

29

Step-by-step explanation:

6 0
3 years ago
A(n) = -1/16 (2) ^n-1 what is the 6th term
Anarel [89]
2^5=32
32*(-1/16)=-2
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8 0
4 years ago
Find the total area of the figure below.
vekshin1

Answer:

a 240

Step-by-step explanation:

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3 0
3 years ago
A theater group made appearances in two cities. The hotel charge before tax in the second city was $ 1500 higher than in the fir
swat32

Answer:

In city one, the hotel charges before taxes were $5,250.

In city two, the hotel charges before taxes were $6,750.

Step-by-step explanation:

Let the hotel charge in the first city be x and in the second city be y.

Given that the hotel charge before tax in the second city was $ 1500 higher than in the first. That can be written as:

y - x = \$1500 ...[1]

The tax in the first city was 5 %, and the tax in the second city was 8.5 %.

The total hotel tax paid for the two cities was $ 836.25

5% of x + 8.5% of y = $836.25

0.05x+0.085y=\$836.25...[2]

Now putting value of y from [1] in to [2]:

y = \$1500+x

0.05x+0.085\times (\$1500+x)=\$836.25

On solving we get :

x = $5,250

Using vakue of x in [1] to find y:

y=\$1500+\$5,250=\$ 6,750

In city one, the hotel charges before taxes were $5,250.

In city two, the hotel charges before taxes were $6,750.

5 0
3 years ago
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