Answer:
The answer is 1.
Step-by-step explanation:
The number is usually in front of the variable, if there is no number, it is a 1.
He saved 30.25 last month. 169 - 48 = 121 divided by 4 = 30.25
APR is different than other compounding periods because you would need to find some equivelancy to compare things at.
Answer:
5/8
Step-by-step explanation:
if 1/8 is used for one batch . for five batch=1/8*5=5/8
To solve this we will divide the given composite figure into three figures. The three figures will be 2 squares and 1 rectangle. Let's find their areas and add them!
![\boxed{ \sf \: area \: of \: square =side ^{2} }](https://tex.z-dn.net/?f=%20%5Cboxed%7B%20%5Csf%20%5C%3A%20area%20%5C%3A%20of%20%5C%3A%20square%20%3Dside%20%5E%7B2%7D%20%20%7D)
![\rm \implies \: area = 3 ^{2}](https://tex.z-dn.net/?f=%20%5Crm%20%5Cimplies%20%5C%3A%20area%20%3D%203%20%5E%7B2%7D%20)
![\rm \implies9](https://tex.z-dn.net/?f=%20%5Crm%20%5Cimplies9)
<em>Thus, The area of 1st square is 9m²...</em>
- The area of second square will be also 9m², because the sides of both squares are equal.
<h3>
Now area of the reactangle⤵️</h3>
- Length = 6m
- Breadth = 7+3=10m
![\sf \: area \: of \: rectangle = length \times breadtg](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20area%20%5C%3A%20of%20%5C%3A%20rectangle%20%3D%20length%20%5Ctimes%20breadtg)
![\tt \dashrightarrow \: area = 10 \times 3](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20area%20%3D%2010%20%5Ctimes%203)
![\tt \dashrightarrow \: area = 30m ^{2}](https://tex.z-dn.net/?f=%20%5Ctt%20%5Cdashrightarrow%20%5C%3A%20area%20%3D%2030m%20%5E%7B2%7D%20)
<em>Thus, The area of rectangle is 30m²....</em>
- Now, Add area of all the figures to get the total area.
![\bf \:total \: area = 9 + 9 + 30 \\ \bf= 48m {}^{2}](https://tex.z-dn.net/?f=%20%5Cbf%20%5C%3Atotal%20%5C%3A%20area%20%3D%209%20%2B%209%20%2B%2030%20%5C%5C%20%20%20%5Cbf%3D%2048m%20%7B%7D%5E%7B2%7D%20)
<h3><em>Therefore, The total area of the composite figure is 48m²...~</em></h3>