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Natalija [7]
3 years ago
15

If a + b+ c = 9 and ab + bc + ca = 26, find a2 + b2 + c2.​

Mathematics
1 answer:
alex41 [277]3 years ago
6 0

Answer:

29

Step-by-step explanation:

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Two pupils each drew a triangle with one side of 6 cm , one side of 10 cm and one side of 7 cm. Must their triangles be congruen
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Answer:

no

Step-by-step explanation:

they can be either side because the numbers are different in the angles

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Step-by-step explanation:

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A standard die is rolled 600 times. How many times would you expect to roll a number
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5 0
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Read 2 more answers
Evaluate the six trigonometric functions of the angle 0.
Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2

18^2 =10^2+\text{opposite}^2

324=100+\text{opposite}^2

Subtract 100 from both sides.

224=\text{opposite}^2

Taking square root on both sides.

4\sqrt{14}=\text{opposite}

Using trigonometric ratio formula:

$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}

$\sin\theta =\frac{4\sqrt{14} }{18}

$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}

$\csc\theta =\frac{18}{4\sqrt{14} }

$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}

$\cos \theta=\frac{10}{18}

$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}

$\sec \theta=\frac{18 }{10}

$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}

$\tan \theta=\frac{4\sqrt{14} }{10}

$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}

$\cot \theta=\frac{10}{4\sqrt{14} }

8 0
3 years ago
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