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3 years ago

Which table represents the relationship between the x-values and the y-values in the equation y = -5x + 1?

Mathematics

1 answer:

Marina86 [1]3 years ago

4 0

Answer:

x=0 the value of y is 1/1 so this line cuts the y axis at y=1.00000. y=0 the value of x is 1/5 our line therefore cuts the axis at x=0.20000

You might be interested in

$1950 plus 15% is what

Fudgin [204]

15% of 1950 = 1950 * 0.15 = 292.5
So, sum would be: 1950 + 292.5 = 2242.5

In short, Your Answer would be $2242.5

Hope this helps!

6 0

3 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago

The real part of the complex number –5 + 3i is

Firlakuza [10]

<span>A complex number is a number of the form a + bi, where i = and a and b are real numbers. For example, 5 + 3i, - + 4i, 4.2 - 12i, and - - i are all complex numbers. a is called the real part of the complex number and bi is called the imaginary part of the complex number.</span>

5 0

3 years ago

Read 2 more answers

Solve i + j + t (3i - j) = -i + s (j)<br> In the context of Vector Equations of a Line

Oksana_A [137]

Answer:

r = i + j + (-2/3)(3i - j)

Step-by-step explanation:

Vector Equation of a line - r = a + kb ; where r is the resultant vector of adding vector a and vector b and k is a constant

if a = i + j ; b = t(3i - j) and r = -i +s(j)

for this to be true all the vector components must be equal

summing i 's

i + 3ti = -i; then t = -2/3

j - tj = sj; then s = 1-t; substitue t; s=1+2/3 = 5/3

so r = i + j + (-2/3)(3i - j) which will symplify to -i + 5/3j

3 0

3 years ago

Can some one help me ??? Anyone ?

Leya [2.2K]

$((-2)^2-4)^3+4\cdot(-5)=\\
(4-4)^3+(-20)=\\
0^3-20=\\
0-20=\\-20$

6 0

3 years ago