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3 years ago

What is true about the sum of the two polynomials?

Mathematics

2 answers:

Arada [10]3 years ago

8 0

9514 1404 393

Answer:

The sum is a binomial with a degree of 3.

Step-by-step explanation:

The sum is ...

(6s²t -2st²) +(4s²t -3st²) = s²t(6 +4) +st²(-2 -3)

= 10s²t -5st² . . . . . . . a binomial of degree 3

The degree of the polynomial is the maximum sum of the degrees of the variables in each term. The first term is degree 2+1 = 3; the second term is of degree 1+2 = 3. The degree of the binomial is 3.

Svetradugi [14.3K]3 years ago

5 0

Answer:

The sum is a binomial with a degree of 3.

Step-by-step explanation:

Yeah the dude or dudette or they above me is right

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STatiana [176]

9/4y-2=25
9/4y-2+2=27+2
9/4y=27
9/4y*4y=27*4y
9=4y*27,
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1/12=y

Answer:y=1/12

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3 years ago

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Does anyone know the answer to this scale and unit conversion GED math problem? Thank you very much!

aliya0001 [1]

Answer:

Flour $5\dfrac{1}{2}\ c$

Sugar $2\dfrac{2}{3}\ c$

Butter $1\dfrac{1}{2}\ c$

Eggs $2$

Baking powder $7\ t$

Vanilla extract $3\ t$

Step-by-step explanation:

There will be 16 people at the party. Each person will eat 3 cookies, so all people will eat $16\cdot 3=48$ cookies.

Given cookie recipe makes 24 cookies, so to make 48 cookies you need

$48:24=2$ portions.

Thus,

1 portion 2 portions

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Sugar $1\dfrac{1}{3}\ c$ $1\dfrac{1}{3}\cdot 2=1\cdot 2+\dfrac{1}{3}\cdot 2=2+\dfrac{2}{3}=2\dfrac{2}{3}\ c$

Butter $\dfrac{3}{4}\ c$ $\dfrac{3}{4}\cdot 2=\dfrac{3}{2}=1\dfrac{1}{2}\ c$

Eggs $1$ $1\cdot 2=2$

Powder $3\dfrac{1}{2}\ t$ $3\dfrac{1}{2}\cdot 2=3\cdot 2+\dfrac{1}{2}\cdot 2=6+1=7\ t$

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3 years ago

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Nonamiya [84]

Answer:

A is the answer

Step-by-step explanation:

You should pay attention to x^3 when you want to talk about infinite.

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2 years ago

If you add 1 to half of 1, then half of 1 to the previous number, and so on, will you ever get to 2?

lisov135 [29]

Answer:

Step-by-step explanation:

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3 years ago

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10($6.75)+7($1.99)+$15.00=$196.43

34kurt

96/43 = 196/43
the equation is false.
Hope this helps!

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3 years ago