The area of each triangular face is 40 square feet
<em><u>Solution:</u></em>
Given that,
Square pyramid has a base area of 64 square feet
The pyramid’s total surface area is 224 square feet
The total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base
<em><u>Therefore, total surface area of square pyramid is given as,</u></em>
Total surface area = base area + 4(Area of traingular face)
Let "x" be the area of each traingular face

Thus area of each triangular face is 40 square feet
Answer:
41 units
Step-by-step explanation:
The diagonal forms a right triangle with the sides, so we can use Pythagorean theorem.
c² = a² + b²
d² = 9² + 40²
d = 41
The diagonal is 41 units long.
For this case we have the following polynomials:

By subtracting both polynomials we have:

What we must do is subtract terms of the same degree.
We have then:
Answer:
will be a polynomial
Answer:
B)41.2
C)0.736
D)6.132
Step-by-step explanation:
B) 412/10=41.2
C)73.6/100=0.736
D)6132/1000=6.132
hope this helps