Answer:
x^2 + {a/(a + b) + (a + b)/a}x + 1 = 0
Delta = {a/(a + b) + (a + b)/a}^2 - 4
= {a/(a + b)}^2 + {(a + b)/a}^2 + 2 - 4
= {a/(a + b)}^2 + {(a + b)/a}^2 - 2
= {a/(a + b) - (a + b)/a}^2
If a is not equal to zero and a is not equal to -b => delta is always larger than 0
=> Solution 1 = - [ {a/(a + b) + (a + b)/a} + |{a/(a + b) - (a + b)/a}| ]/2
=> Solution 2 = - [ {a/(a + b) + (a + b)/a} - |{a/(a + b) - (a + b)/a}| ]/2
Hope this helps!
:)
To solve this we are going to use the formula for the lateral surface area of a regular pyramid:
where
is the lateral surface area.
is the perimeter of the base.
is the slant height.
We know for our problem that
and
, so lets replace those values in our formula and solve for
:
Now we know that the perimeter of the base of our regular triangular pyramid is 33 cm. Remember that the perimeter of a triangle is the sum of its 3 sides. Since our pyramid is regular, its base will be an equilateral triangle, so to f<span>ind the length of the base edge, we just need to divide the perimeter by 3:
</span>
<span>
We can conclude that the length of the base edge of our regular triangular pyramid is
11 cm.</span>
Answer:
77.1
Step-by-step explanation:
Let be the height of the model. We have . Hence, we have .
Your question was already in slope intercept form. See picture for photo of the graph and mark me as brainliest if you think i helped :)
The correct answer is true