Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
right isosceles
rs:34&rs=rt+st
rt:17
st:17
ab=[(x(a)-x(b))+(y(a)+y(b))]
Answer:
it 6 because I said so you can't be alone 3PM if you get your school work done in your sleep all the 378feet and I have to eat a
Answer:the second one is the answer
Step-by-step explanation:trust me
Answer:
20 degrees
Step-by-step explanation:
If BD is the angle bisector of ABC, then ABD must equal half of that. 40/2=20 degrees. Hope this helps!
