Answer:
81.6
Step-by-step explanation:
mean/average of her grade = sum of all scores/the number of scores
= (93+82+74+92+67)/5
= 81.6
We can use elimination for these set of systems.
First, we need to set up our variables.
Belts=b
Hats=h
Now, the situation is 6 belts and 8 hats for $140. The situation after is 9 belts and 6 hats for $132.
Let’s set up our system of equations.
6b+8h=140
9b+6h=132
We need to eliminate a variable. Since b has coefficients of 6 and 9, we can easily eliminate b by multiplying the top equation by 3 and the bottom by -2.
18b+24h=420
-18b-12h=-264
Now let’s add.
12h=156
Let’s divide to get h by itself.
156/12=13=h
So a hat costs $13. We need to put in 13 for one of the equations so we can find the cost of a belt.
9b+6(13)=132
9b+78=132
We need b by itself.
9b=54
54/9=6
Belts are $6
We can also use the first equation to check our answers.
6(6)+8(13)
36+104
140.
So, the price of a belt is $6 while the price of a hat is $13.
Sry but I need more information to answer the question. So so sry!
Answer:
Log₆ (A⁵C² / D⁶) = –13
Step-by-step explanation:
From the question given above,
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
Log₆ (A⁵C² / D⁶) =?
Recall:
Log MN / U = Log M + Log N – Log U
Therefore,
Log₆ (A⁵C² / D⁶) = Log₆ A⁵ + Log₆ C² – Log₆ D⁶
Recall:
Log Mⁿ = nLog M
Thus,
Log₆ A⁵ + Log₆ C² – Log₆ D⁶
= 5Log₆ A + 2Log₆ C – 6Log₆ D
Log₆ A = 1
Log₆ C = 3
Log₆ D = 4
= 5(1) + 2(3) – 6(4)
= 5 + 6 – 24
= 11 – 24
= –13
Therefore,
Log₆ (A⁵C² / D⁶) = –13
