The height of the building to the nearest tenth of a meter is; 13 m
<h3>How to make use of Cosine Rule?</h3>
The slant line from the top of Trevor's head to the base of the building is gotten from Pythagoras theorem;
15/x = sin 36°
x = 15/sin 36
x = 25.52 m
Angle between that slant line and base of building is;
90 - tan⁻¹(1.5/14) = θ
θ = 83.88°
Remaining angle of the bigger triangle is;
180 - (36 + 83.88) = 60.12°
Thus, if the height of the building is h, then;
h/sin 36 = 25.52/sin 60.12
h = 13 m
Read more about Cosine Rule at; brainly.com/question/4372174
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Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:
First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;
Divide by m to isolate 
.
To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
Thanks, you two, bless you.
Answer:The answer is 10!
Step-by-step explanation:
