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malfutka [58]
3 years ago
5

The rectangle below has an area of x^2-15x+56x square meters and a length of x-7 meters.

Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0
Heya \: \: ! \\ \\ \\ Area \: of \: rectangle \: = Length \: \times Width \\ \\ We \: are \: given \: that \: , \\ \\ Length \: = \: \: ( \: x - 7 \: ) \: metres \\ Area \: \: \: \: \: = \: \: \: ( \: {x}^{2} - 15x + 56 \: ) \: square \: meters \\ \\ Therefore \: \: , \: \\ {x}^{2} - 15x + 56 = ( \: x - 7) \times Width \\ \\ Width = \frac{ ({x}^{2} - 15x + 56 )}{(x - 7)} \\ \\ Width = \frac{(x - 7)(x - 8)}{(x - 7)} \\ \\ \\ Width = ( \: x - 8 \: ) \: \: m \: \: \: \: \: \: \: \: \: Ans.
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vladimir1956 [14]

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Step-by-step explanation:

Data

∠A = 20°

∠B = 46

a = 7

b = x

Process

To solve this problem use, the law of sines. This law states that the ratio of a side of a triangle to the sine of the opposite angle is the same for all three sides.

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6 0
4 years ago
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