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malfutka [58]
2 years ago
5

The rectangle below has an area of x^2-15x+56x square meters and a length of x-7 meters.

Mathematics
1 answer:
Gennadij [26K]2 years ago
3 0
Heya \: \: ! \\ \\ \\ Area \: of \: rectangle \: = Length \: \times Width \\ \\ We \: are \: given \: that \: , \\ \\ Length \: = \: \: ( \: x - 7 \: ) \: metres \\ Area \: \: \: \: \: = \: \: \: ( \: {x}^{2} - 15x + 56 \: ) \: square \: meters \\ \\ Therefore \: \: , \: \\ {x}^{2} - 15x + 56 = ( \: x - 7) \times Width \\ \\ Width = \frac{ ({x}^{2} - 15x + 56 )}{(x - 7)} \\ \\ Width = \frac{(x - 7)(x - 8)}{(x - 7)} \\ \\ \\ Width = ( \: x - 8 \: ) \: \: m \: \: \: \: \: \: \: \: \: Ans.
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Rosario and Enrqiue are in the same mathematics
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Answer:Enrqiue's average was higher than Rosario's average by 3

Step-by-step explanation:

Rosario's average= sum of 78, 77, 64, 86, and 70/ no of scores= 375/5= 75

Enrique's average=sum of 90, 61, 79, 73, and 87/ no of scores = 390/5=78

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3 years ago
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Bond [772]

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2 years ago
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never [62]
<h3>1 Answer: v = -130</h3>

=============================================================

Explanation:

Because we're given multiple choices to pick from, we can go through each to do trial and error.

For instance, if v = 52, then

v/13 < -7

52/13 < -7

4 < -7

but that's a false statement since 4 is not smaller than -7. Use a number line to see this. You should have -7 to the left of 4, showing that -7 is the smaller value.

Because 4 < -7 is false, this means v/13 < -7 is false when v = 52. This rules out v = 52. You should find that v = 26 and v = -39 won't work for similar reasons.

Only v = -130 works since...

v/13 < -7

-130/13 < -7

-10 < -7

This is true because -10 is to the left of -7 on the number line.

-------------------------------------------------

Another approach:

We have some unknown number v, and we're dividing by 13 to get the expression v/13. To undo this, we multiply both sides by 13

v/13 < -7

13*(v/13) < 13*(-7) .... multiply both sides by 13

v < -91

So any solution to the original inequality must be smaller than -91. This allows us to rule out v = 52, v = 26 and v = -39.

The value v = -130 is smaller than -91, so it satisfies v < -91. Therefore, v = -130 is a solution to the original inequality.

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