3 years ago

See attachment, answer please.

Mathematics

1 answer:

Anton [14]3 years ago

6 0

Answer:

4.5

Step-by-step explanation:

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The strength of a cable is proportional to the square of its diameter. If a 2-cm cable will support 800kg, how much will a 3-cm

xz_007 [3.2K]

Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg

3 0

3 years ago

ALGEBRA HELP PLEASE!!!! I DO NOT UNDERSTAND <br> Question: What is the range of this function?

Olegator [25]

Answer is D {-8, -3, 5, 7 }

hope it helps

8 0

2 years ago

Someone please help me answer this!!

dybincka [34]

Answer:

17.9 units is the answer

Step-by-step explanation:

points are (-7,-2) and (9,6)

Pythagorean theorem can be written as,

$d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d=\sqrt{9-(-7))^2 + (6-(-2))^2}\\\\d=\sqrt{(16)^2+(8)^2} \\\\d=\sqrt{256+64} \\\\d=\sqrt{320} \\\\d=17.88$

Rounding off,

d = 17.9 units

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bxln%5E%7Bp%7Dx%20%7D" id="TexFormula1" title=" \int \frac{dx}{xl

Eva8 [605]

Substitute $u=\ln x$ , so that $\mathrm du=\dfrac{\mathrm dx}x$ . The integral is then equivalent to

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}$

Then transforming back to $x$ gives

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\begin{cases}\dfrac{\ln^{p+1}x}{p+1}+C&\text{for }p\neq1\\\\\ln|\ln x|+C&\text{for }p=1\end{cases}$

4 0

3 years ago

Please help with this question

11111nata11111 [884]

Answer:

QR and CD

Step-by-step explanation:

TQRS is similar to BCDE. Align the letters.

T Q R S

B C D E

Some examples of corresponding sides.

TS and BE

TQ and BC

6 0

2 years ago