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julsineya [31]
3 years ago
8

Determine whether the relation below is also a function.

Mathematics
1 answer:
Rufina [12.5K]3 years ago
7 0
It is not a function because it does not pass the vertical line test. For every x value there must be only 1 y value but this graph is not a function because there are 2 y values for every y value.
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Determine the exact value of sin 13pi/12
ohaa [14]
To answer the problem above, convert the given angle to an equivalent angle with the unit of degrees.
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X2-5x+10=0 is it quadratic equation? how can i identify the value of a,b,c? help
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Determine the end behavior of P(x)=3x
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Answer:

As x ⇒-∞, P(x) ⇒ -∞

As x ⇒ ∞, P(x) ⇒ ∞

Step-by-step explanation:

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P(x) = 3(-∞) = -3(∞) = -∞

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  The 'y' values of the function increase towards positive infinity as the 'x' values approach positive infinity

6 0
3 years ago
The ratio of the side length of square a to the side length of square b is 3:5. the perimeter of square b is 60 feet. what is th
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Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,
Leya [2.2K]

Answer:  \dfrac{1}{3}[\ln (x+1)+\ln(x-1)]

Step-by-step explanation:

Properties of logarithm :

  1. \log (ab)= \log a+\log b
  2. \log(\dfrac{a}{b})=\log a-\log b
  3. \log a^n= n\log a

The given expression in terms of Natural log : \ln (x^2 - 1)^{\frac{1}{3}}

This will become \dfrac{1}{3}\ln (x^2 - 1)      [ By using Property (3)]

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=\dfrac{1}{3}\ln ((x+1)(x-1))   [\because a^2-b^2=(a+b)(a-b)]

=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]   [ By using Property (1)]

Hence, the simplified expression becomes \dfrac{1}{3}[\ln (x+1)+\ln(x-1)] .

5 0
3 years ago
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