<span>Coders using encoder software:
To enhance their productivity</span><span>
Speed and Efficiency
</span><span>Accuracy and consistency
</span>
Encoding is done to reduce the number of bit to be transmitted and save bandwidth .can be fairly complex and contain some delicate parts. This makes them
less tolerant of mechanical abuse and restricts their allowable temperature.
<span>including
increased productivity, accuracy, and efficiency in coding and the
consistent application of coding rules. However, there is a cost to the
software, but savings can be seen in other areas.</span>
Answer:
yes administrators have to be concerned
Explanation:
It is necessary for countermeasures to be taken against DoS attacks
The types of attacks that can still occur are:
If the network connection get to be overloaded, there could be flash crown of this computer system and fraudulent activities maybe initiated. By flash crowd we mean that the there is a great deal of traffic on the system and this could cause the network connection to be destroyed.
To reduce the impact of this kind of attacks,
1. there should be enough or excess network bandwidth and distributed servers should be replicated if there is a possibility that network could get to be overloaded.
2. restriction is more commonly done on sporting sites. Restriction brings about an increase in implementation cost.
3. The impact of this type of attack can be reduced by stopping unwanted traffic throught the implementation of filters
4. Use strong antivirus on computer sytems that are used to connect to the internet
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
Answer:
True
Explanation:
Using the t-distribution table, the critical value for a one-tailed test with 6 degrees of freedom and 0.05 significance level is 2.447
Conclusion:
Reject the null hypothesis because the test statistic 2.045 is less than the critical value 2.447
