Question

What is the area of a rectangle with vertices at ​ (−6, 3) ​, ​ (−3, 6) ​ , (1, 2) , and (−2, −1) ? Enter your answer in the box. Do not round any side lengths.

Answer 1

You would have to find the magnitude of the sides to find out the area. 

A=(-6, 3) 
B= (-3,6) 
C= (1, 2) 
D= (-2, -1) 

A-B = √(x₁-x₂)²+(y₁-y₂)² 
=√(-6+3)²+(3-6)²
=√9+9
=√18 
=4.24

C-D=√(x₁-x₂)²+(y₁-y₂)² 
=√(1+2)²+(2+1)²
=√9+9 
=4.24 

Area= lxw 
A=√18x√18
a=18 

Hope I helped :) 

Answer 2

For those of you who's vertices read as (6,-3), (3,-6), (-1,-2), and (2,1)  AKA the Opposite of this question, your answer is:

24

I took the test and that is what I got.