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2 years ago

Help Help Help Help Help FAST GO ZOOOOOOOOOOOOM WITH THIS QUESTION PLEASE

Mathematics

2 answers:

JulsSmile [24]2 years ago

5 0

60+x=90 all complementary angles add up to 90 degrees

xxMikexx [17]2 years ago

3 0

Answer:

A. 60+x=90

Step-by-step explanation:

Complimentary angles are angles that add to 90.

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Please help!!!! <br> Solve the following equation for m:<br> m/3=6

RSB [31]

Answer:

$\frac{m}{3} = 6 \\ m = 6 \times 3 \\ = 18$

5 0

3 years ago

Read 2 more answers

What is the fourth proportion of 2,5 and 6

ivanzaharov [21]

Answer:

The fourth proportion is 15

2:5 :: 6 : 15

5 0

3 years ago

The cost of a car battery costs $35 wholesale for the automotive store to buy, but they need to markup the cost 40% for the reta

lara31 [8.8K]

Answer:

The markup amount is $14 and the retail price is $49.

Step-by-step explanation:

You can use the following formula to find the retail price with the information provided:

Retail price=Cost*(100%+markup %)

Cost=35

Markup %= 40%

Now, you can replace the values in the formula:

Retail price=35*(140%)

Retail price=49

Now, you can subtract the cost from the retail price to find the markup amount:

49-35=14

According to this, the answer is that the markup amount is $14 and the retail price is $49.

8 0

3 years ago

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago

(2x+3)+(5x17)+90=180

klasskru [66]

Answer:

x=10

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers