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PtichkaEL [24]
3 years ago
13

Geometry Help:

Mathematics
1 answer:
notka56 [123]3 years ago
6 0

1) E&B and K&A

2) X&L and E&E

3) K&L and A&F

4) C&L and I&E

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Which of the following is a monomial? A.2x+yz, b.2+xyz c.2xyz 2 d.2x
Dennis_Churaev [7]
D ----> 2X is a monomial
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An octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in cm and the area is 392.4 in2. A second octagon has c
Lana71 [14]
If the figures/solids are similar, the ratio of the areas is equal to the square of the ratio of the corresponding sides. Let x be the area of the second figure. The equation that would best allow us to answer this item is,
                      (394.2 in² / x in²) = (10.9 / 21.8)²
The value of x from the equation is 1576.8 in².

Thus, the nearest answer is the second choice. 
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3 years ago
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John had 2/3 of his homework completed Sarah had 5/10 Alex 7/ 8 Michelle 1/2 who completed the most of the homework assignment
spayn [35]
Alex did the most amount of the homework assignment because if you turn them all into a fraction with a common denominator, Alex would have the most.

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8 0
3 years ago
I need it urgent now
Ray Of Light [21]

So the answer for number 3 is p because p is the only one right on top of 4

But I dont know the answer for number 4 but I think its 2 I might be way off but its my guess.

Hope number 3 helps

6 0
3 years ago
Pls help!!!!!!!! Will give brainliest!!!!!!!!!!!
prohojiy [21]
Okay so lets look at the equation given
a ^{2} + {b}^{2} = {c}^{2}
this is the Pythagorean theorem, this equation holds true to all right angle triangles.

for the "a" and "b" terms must be the two shortest lengths and "c" must be the longest length.
why? because "c" represents the hypotenuse in this theorem and the hypotenuse is by definition the longest side of a right triangle.

(side note: always draw a picture, it helps a lot if you doodle a bit to get an idea of what you are working with)

we are given three lengths : 3 , 4, and 5 (im ignoring the measurements for now)

we can look at it two ways with a picture and through algebra

try to draw a right triangle with the given info. you'll see there are only two cases were this is possible the picture above is one case where this is not possible

now we can look at this algebraically
a = 3 \\ b = 4 \\ c = 5
(but "a" and "b" can swap lengths)

now with the Pythagorean theorem we can see how this plays out
{a}^{2} + {b}^{2} = {c}^{2} \\ {3 }^{2} + {4}^{2} = {5 }^{2} \\ 9 + 16 = 25 \\ 25 = 25
and heres with "a" and "b" lengths swapped
{4}^{2} + {3}^{2} = {5}^{2} \\ 16 + 9 = 25 \\ 25 = 25
now here's a case when we let 5 , our longest length , become a leg and let one our shorter lengths take the place of "c"

a = 5 \\ b = 3 \\ c = 4 \\ {5}^{2} + {3}^{2} = {4}^{2} \\ 25 + 9 = 16 \\ 34 = 16 \:
obviously 34 does not equal 16

hope this helped you out

4 0
3 years ago
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