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Troyanec [42]
2 years ago
5

Divide: (12x4 + 9x3 – 10x2) ÷ 3x3

Mathematics
2 answers:
vlada-n [284]2 years ago
8 0

Answer:

55

Step-by-step explanation:

(12 \times 4 + 9 \times 3 - 10 \times 2) \div 3 \times 3 \\ (48 + 9 \times 3 - 10 \times 2) \div 3 \times 3 \\ (48 + 27 - 10 \times 2) \div 3 \times 3 \\ (48 + 27 - 20) \div 3 \times 3 \\ 55  \div 3  \times 3 \\  \frac{55}{3}  \times 3 \\ =55

\boxed{\green{= 55}}

Salsk061 [2.6K]2 years ago
4 0

Answer: 6.111

Step-by-step explanation: first break it down

(12x4 + 9x3 – 10x2) ÷ 3x3

(48 + 27 - 20)/9

(75 - 20)/9

55/9

6.111

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Hey There!

To find how many seats are needed to be added, you need to subtract 15,340 by 13,451. You need to find the difference between the seats you need and the seats you have. So...

15,340-13,451= 1,889

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Hope This helped!

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3 years ago
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What is :190% times $20,000
denis23 [38]

In this question, we would be multiplying.

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Solve:

20000 · 1.9 = 38,000‬

Answer:

38,000‬

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3 years ago
1) What is the solution of the inequality?<br> 42-8 - 22-24
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Answer:

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Step-by-step explanation

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Two cars start at a given point and travel in the same direction at average speeds of 45 miles per hour and 52 miles per hour (s
Citrus2011 [14]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
3 years ago
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