Find the area of shaded region where o is the centre of the circle
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Answer:
4 liters of 60% solution; 2 liters of 30% solution
Step-by-step explanation:
I like to use a simple, but effective, tool for most mixture problems. It is a kind of "X" diagram as in the attachment.
The ratios of solution concentrations are 3:6:5, so I've used those numbers in the diagram. The constituent solutions are on the left; the desired mixture is in the middle, and the numbers on the other legs of the X are the differences along the diagonals: 6 - 5 = 1; 5 - 3 = 2. This tells you the ratio of 60% solution to 30% solution is 2 : 1.
These ratio units (2, 1) add to 3. We want 6 liters of mixture, so we need to multiply these ratio units by 2 liters to get the amounts of constituents needed. The result is 4 liters of 60% solution and 2 liters of 30% solution.
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If you're writing equations, it often works well to let the variable represent the quantity of the greatest contributor—the 60% solution. Let the volume of that (in liters) be represented by v. Then the total volume of iodine in the mixture is ...
... 0.60·v + 0.30·(6 -v) = 0.50·6
... 0.30v = 0.20·6 . . . . subtract 0.30·6, collect terms
... v = 6·(0.20/0.30) = 4 . . . . divide by the coefficient of v
4 liters of 60% solution are needed. The other 2 liters are 30% solution.
After 6 years the investment is $5555.88
Step-by-step explanation:
A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?
The formula used to find future value is:
where A(t) = Accumulated amount
P = Principal Amount
r = annual rate
t= time
n= compounding periods per year
We are given:
P = $3600
r = 7.5 %
t = 6
n = 1
Putting values in formula:
So, After 6 years the investment is $5555.88
Keywords: Compound Interest formula
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