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abruzzese [7]
3 years ago
13

The percentage of students who attended the talent show for years 2018 to 2013 I shown year | percent of students 2008 | 83% 200

9 | 85% 2010 | 89% 2011 | 84% 2012 | 88% 2013 | 81% This year the school has a total of 400 students. How many students do you expect to attend the talent show this year explain how you found your answer please!:)
Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

Students = 340

Step-by-step explanation:

Given

2008 \to 83\%

2009 \to 85\%

2010 \to 89\%

2011 \to 84\%

2012 \to 88\%

2013 \to 81\%

n = 400

Required

The expected number of students

First, calculate the average attendance in the 6 years of the talent show.

\bar x = \frac{83\% + 85\% + 89\% + 84\% + 88\% + 81\%}{6}

\bar x = \frac{510\%}{6}

\bar x = 85\%

The expected number of students is:

Students =n * \bar x

Students = 400 * 85\%

Students = 340

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There are several ways two triangles can be congruent.

  • \mathbf{AC = BD}<em> congruent by SAS</em>
  • \mathbf{\angle ABC \cong \angle BAD}<em> congruent by corresponding theorem</em>

In \mathbf{\triangle AOL} and \mathbf{\triangle BOK} (see attachment), we have the following observations

1.\ \mathbf{AO = DO} --- Because O is the midpoint of line segment AD

2.\ \mathbf{BO = CO} --- Because O is the midpoint of line segment BC

3.\ \mathbf{\angle AOB =\angle COD} ---- Because vertical angles are congruent

4.\ \mathbf{\angle AOC =\angle BOD} ---- Because vertical angles are congruent

Using the SAS (<em>side-angle-side</em>) postulate, we have:

\mathbf{AC = BD}

Using corresponding theorem,

\mathbf{\angle ABC \cong \angle BAD} ---- i.e. both triangles are congruent

The above congruence equation is true because:

  1. <em>2 sides of both triangles are congruent</em>
  2. <em>1 angle each of both triangles is equal</em>
  3. <em>Corresponding angles are equal</em>

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3 0
2 years ago
0.0660 into scientific notation
Yakvenalex [24]

Answer:

0.0660 = 6.60 x 10-2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
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