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IrinaK [193]
3 years ago
14

A bakery needs to make 5 batches of bagels before opening in 3 hours. Each batch of bagels takes 3 4 hour to make.

Mathematics
2 answers:
pentagon [3]3 years ago
8 0

No because 3/4 x 5 unequal 3 so they would have 4 batches of bagels.

S_A_V [24]3 years ago
7 0

Answer:

The closest answer is B, 3.75 is closest to 4, if it isn't that, then choose D

Step-by-step explanation:

We need 5 batches: 3 hours.

                1 batch: 3/4 Hours

when 5 batches is done: 3.75

So no, We will not make it in time.

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If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

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Answer:

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