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IrinaK [193]
3 years ago
14

A bakery needs to make 5 batches of bagels before opening in 3 hours. Each batch of bagels takes 3 4 hour to make.

Mathematics
2 answers:
pentagon [3]3 years ago
8 0

No because 3/4 x 5 unequal 3 so they would have 4 batches of bagels.

S_A_V [24]3 years ago
7 0

Answer:

The closest answer is B, 3.75 is closest to 4, if it isn't that, then choose D

Step-by-step explanation:

We need 5 batches: 3 hours.

                1 batch: 3/4 Hours

when 5 batches is done: 3.75

So no, We will not make it in time.

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After dis if you get the answer right you get 50 points
svetoff [14.1K]

Answer:

5

Step-by-step explanation:

First you have 24-(5+9)/2

So do 5+9=14

24-14=10

10/2=5

answer is 5

7 0
2 years ago
Read 2 more answers
Which statement best explains the relationship between lines FG and HJ?
murzikaleks [220]

Answer:

(D)

Step-by-step explanation:

From the figure, we have

The coordinates of the point F are: (-4,1).

The coordinates of the point G are: (0,-2)

The coordinates of the point J are: (0,4) and

The coordinates of the point H are: (-4,-2).

Now, the slope of the line FG is :

S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

S=\frac{-2-1}{0+4}

S=\frac{-3}{4}

And, the slope of the line HJ is:

S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

S=\frac{-2-4}{-4-0}

S=\frac{3}{2}

Now, the slope of FG=\frac{1}{slope of HJ}

\frac{-3}{4}=\frac{2}{3}

which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.

6 0
3 years ago
Read 2 more answers
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
Please check my answers. Thanks
vaieri [72.5K]

1) should be second option

CD→

2) None of these

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3 years ago
Help asap! giving brainliest!
saw5 [17]

Answer:

Step-by-step explanation:

2

would you like to know how I got that?

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