Answer:
simplified it's: y = 12x + 165
Step-by-step explanation:
3(55) + x(12) = y
Answer:
27/40
Step-by-step explanation:
Probability of picking heart: 3 hearts/ 10 total
Probability of picking club: 4 clubs/ 9 left over cards
3/10 divided by 4/9= 27/40
Hope this helped
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a. The reason why this question is a binomial experiment is based on the fact that it is made up of an independent sample, it has a number that is fixed and a probability.
Each event is made up of two outcomes and they are random with the same success rate.
<h3>b. How to solve probability that exactly 5 had a bachelor</h3>
we have the following data n = 12, p = 0.27 and k = 5
We have to use the function to solve electronically
binompdf(n,p,k)
input the values
= binompdf(12,0.27,5)
This gives us
= 0.1255
<h3>(C) Probability that fewer than 5 have bachelor</h3>
We use the formula below
= binompdf(12,0.27,5-1)
This is = 0.7984
D. Probability of at least 5
1 - probability of fewer than 5
= 1 - 0.7984
= 0.2016
How to solve for the Mean = n*p
n = 12 , p = 0.27
Mean = 12*0.27 = 3.24
and
standard deviation = √npq
n = 12, p = 0.27 , q = 1- 0.27
= 0.73
sd = √12*.27*.73
= 1.54
Read more on binomial experiment here:
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Among all the filled solutions first four solutions, sixth , eight , elventh to thirteenth are correct.
Given twenty expressions and we are required to find the value of expressions when x=0 and x=1.
Expression is combination of numbers, fractions, coefficients, mostly not found in equal to form.
1)2x+3-2+x
when x=0,
=2*0+3-2+0
=1
when x=1,
=2*1+3-2+1
=4
2)4x-5-2x
when x=0,
=4*0-5-2*0
=-5
when x=1,
=4*1-5-2*1
=-3
3)2-3(x+1)+4x
when x=0
=2-3(0+1)+4*0
=-1
when x=1
=2-3(1+1)+4*1
=0
4)4+3x-x-1
when x=0
=4+3*0-0-1
=3
when x=1
=4+3*1-1-1
=5
5)6x-5-6x
when x=0
=6*0-5-6*0
=-5
6) 5(x+1)-x+2
when x=0
=5(0+1)-0+2
=7
when x=1
=5(1+1)-1+2
=11
7) 2x-7+5x-3
when x=0
=2*0-7+5*0-3
=-10
when x=1
=2*1-7+5*1-3
=-3
8) 3+2x-3
when x=0
=3+2*0-3
=0
when x=1
=3+2*1-3
=2
9) 14-2x-5x+2
when x=0
=14-2*0-5*0+2
=16
when x=1
=14-2*1-5*1+2
=9
10) 5-4x(1+3)+7x
when x=0
=5-4*0(1+3)+7*0
=5
when x=1
=5-4*1(1+3)+7*1
=-4
11) 3x+1
when x=0
=3*0+1
=1
when x=1
=3*1+1
=4
12) 2x+5
when x=0
=2*0+5
=5
when x=1
=2*1+5
=7
13)x-3
when x=0
=0-3
=-3
when x=1
=1-3
=-2
14)2x+3
when x=0
=2*0+3
=3
when x=1
=2*1+3
=5
15) 12x-5
when x=0
=12*0-5
=-5
when x=1
=12*1-5
=7
16) 4x+7
when x=0
=4*0+7
=7
when x=1
=4*1+7
=11
17) 6x-5
when x=0
=6*0-5
=-5
when x=1
=6*1-5
=1
18) 2x
when x=0
=2*0
=0
when x=1
=2*1
=2
19) 16-5x
when x=0
=16-5*0
=16
when x=1
=16-5*1
=11
20) 5-9x
when x=0
=5-9*0
=5
when x=1
=5-9*1
=-4
Hence it is found that among all the filled solutions first four solutions, sixth , eight , elventh to thirteenth are correct.
Learn more about expressions at brainly.com/question/723406
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Answer:
x = 2, because 16/8 = (8x)/8
Step-by-step explanation:
Devide both sides by the coefficient of variable