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1 year ago

3.5+2=2x-10help me HELP ME JIGGABOOS

Mathematics

1 answer:

Genrish500 [490]1 year ago

5 0

3.5 + 2 = 2x - 10
5.5 = 2x -10
+10 +10
—————————
15.5 = 2x
—— ——
2 2

7.75 = x

7.75 is the answer

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3 years ago

Read 2 more answers

Given: x - 6.3333 ≤ 1.5 .

Inessa05 [86]

Answer:

$x$ or $(-\infty, 47/6]$

Step-by-step explanation:

Note that $6.3333 = 6 1/3 = 19/3 = 38/6$ .

Also, note that $1.5 = 1 1/2 = 3/2 = 9/6$ .

So, the inequality is really equal to $x-38/6$ .

We can then add $38/6$ to both sides to get $x$ .

So, the solution is $x$ , or in interval notation, $(-\infty, 47/6]$

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3 years ago

What is the solution to the system of equations below? -5x-y=5 x=7y-1

lisov135 [29]

Answer:

The answer in point form is (-1,0)

6 0

3 years ago

I NEED HELP PLEASE, THANKS! :)

Alenkasestr [34]

Answer:

Option A

Step-by-step explanation:

This is a great question!

The first thing we want to do here is to graph the system of " inequalities " -

$\begin{bmatrix}2x+9y\le \:100\\ 9x+y\le \:54\end{bmatrix}$

As x is ≥ 0, respectively y ≥ 0, it makes things a lot simpler, as it kind of restricts us to quadrant 1, but not entirely.

First change each inequality to " slope - intercept " form, as such -

$2x + 10y \leq 100,\\10y \leq 100 - 2x,\\y \leq - 1 / 5x + 10\\----------\\9x + y \leq 54,\\y \leq - 9x + 54$

The graphed solutions would be in the attachment. I have colored the region with which the two intersect, and the fact that we are limited to quadrant 1. In this colored region there are 3 major points, ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ). We have to determine which of these are are maximum points, as the minimum are the same. Substitute these values ( ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ) ) into the equation f( x, y ) = 10x + 4y,

$f ( x, y ) = 10( 5 ) + 4( 9 ),\\f ( x, y ) = 86 -\\f ( x, y ) = 10( 0 ) + 4( 10 ),\\f ( x, y ) = 40 -\\f ( x, y ) = 10( 6 ) + 4( 0 ),\\f ( x, y ) = 60$

( 5, 9 ) resulted in the greatest amount, 86. That would make it our maximum point -

Solution = Option A

3 0

3 years ago