Question

Question attached,

Answer 1

Answer:

Step-by-step explanation:

$(a)\\ \\ (i)\ \sqrt{3}=3^p\\ \\ 3^{\frac{1}{2}}=3^p\\ \\ p=\frac{1}{2}\\ \\ (ii)\ \frac{1}{9}=3^q\\ \\ 3^{-2}=3^q\\ \\ q=-2\\ \\ (b)\\ \\ 3^{\frac{1}{2}(3^x)=\frac{1}{9}\\ \\ 3^{\frac{1}{2}+x}=3^{-2}\\ \\ \frac{1}{2}+x=-2\\ \\ x=-1.5$