Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² = 
t = 
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² = 
t = 
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² = 
t = 
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
Answer:
Step-by-step explanation:
t2/t1=r
-10/2=-5
2*-5=-10
<span>divide the numerator by the denominator to find its decimal equivalent.</span>
Answer:
Step-by-step explanation:
The segment joining an original point with its rotated image forms a chord of the circle of rotation containing those two points. The center of the circle is the center of rotation.
This means you can find the center of rotation by considering the perpendicular bisectors of the segments joining points with their images. Here, the only proposed center that is anywhere near the perpendicular bisector of DE is point M.
__
Segment AD is perpendicular to corresponding segment FE, so the angle of rotation is 90°. (We don't know which way (CW or CCW) unless we make an assumption about which is the original figure.)
Answer:
Step-by-step explanation:
Apply the Midsegment Theorem:
![\displaystyle \frac{1}{2}[96 - 4x]° = [5x + 6]° → [48 - 2x]° = [5x + 6]° → -42 = -7x; 6 = x \\ \\ [48 - 2(6)]° = [48 - 12]° = 36° \\ \\ AND/OR \\ \\ [5(6) + 6]° = [30 + 6]° = 36°](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B2%7D%5B96%20-%204x%5D%C2%B0%20%3D%20%5B5x%20%2B%206%5D%C2%B0%20%E2%86%92%20%5B48%20-%202x%5D%C2%B0%20%3D%20%5B5x%20%2B%206%5D%C2%B0%20%E2%86%92%20-42%20%3D%20-7x%3B%206%20%3D%20x%20%5C%5C%20%5C%5C%20%5B48%20-%202%286%29%5D%C2%B0%20%3D%20%5B48%20-%2012%5D%C2%B0%20%3D%2036%C2%B0%20%5C%5C%20%5C%5C%20AND%2FOR%20%5C%5C%20%5C%5C%20%5B5%286%29%20%2B%206%5D%C2%B0%20%3D%20%5B30%20%2B%206%5D%C2%B0%20%3D%2036%C2%B0)
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